Impulse of ball from bat when playing baseball

AI Thread Summary
When a baseball player hits a home run, the impulse received by the baseball from the bat is not greater than the impulse received by the bat from the baseball. This conclusion is supported by the law of conservation of momentum, which states that momentum is conserved in a closed system. Newton's third law also reinforces this idea, indicating that for every action, there is an equal and opposite reaction. Therefore, the impulse experienced by both the bat and the ball must be equal. The discussion confirms that the initial assertion is false.
student000
Messages
7
Reaction score
0
Is it true or false that when a baseball player hits a home run, the baseball receives a greater impulse from the bat than the bat does from the ball?

I think the answer is false because of the law of conservation of momentum.
 
Physics news on Phys.org


student000 said:
I think the answer is false because of the law of conservation of momentum.
Good. Even more direct is to consider Newton's 3rd law (which leads to conservation of momentum).
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top