In a race down inclined plane why does a cube reach bottom first?

AI Thread Summary
In a race down an inclined plane, a cube reaches the bottom first compared to a solid cylinder due to differences in energy conversion; the cube slides without converting energy into rotational kinetic energy, while the cylinder rolls and does. This scenario assumes the cube slides on a frictionless surface, while the cylinder rolls on a surface with friction. The discussion highlights that the object with the smaller moment of inertia will win the race, regardless of mass or radius, as long as it rolls without slipping. The moment of inertia for the solid cylinder is lower than that of a hoop, which affects their speeds. Overall, the cube's lack of rotational energy conversion allows it to descend faster than the rolling cylinder.
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In a race down inclined plane why does a cube reach bottom first? The other object is a solid cylinder. The cylinder rolls without slipping, and the cube slides. The cylinder has radius R, and a cube has radius R. Does this depend on the mass of the objects? Is it because since the cube doesn't slide, none of its energy is converted into rotational KE as happens in the case of the cylinder?
 
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positron said:
Is it because since the cube doesn't slide, none of its energy is converted into rotational KE as happens in the case of the cylinder?
That's right. Of course you have to "cheat" a bit and assume that the cube slides down a frictionless surface, while the cylinder rolls down a surface with friction. (Otherwise the cylinder would just slide down also.)

For fun: Solid cylinder versus hoop--which wins that race? Does it depend on mass? On radius? (Figure it out.)
 
Doc Al said:
That's right. Of course you have to "cheat" a bit and assume that the cube slides down a frictionless surface, while the cylinder rolls down a surface with friction. (Otherwise the cylinder would just slide down also.)
For fun: Solid cylinder versus hoop--which wins that race? Does it depend on mass? On radius? (Figure it out.)

It be the one with the smaller moment of inertia. I for a solid cylinder of the same radius and mass as the hoops is larger, so it would go down faster. I for the solid cylinder is 1/2*M*R^2 and I for the hoops is just M*R^2. If the moment of inertia of the cube were greater than the cylinder, would it reach the bottom second?
 
positron said:
It be the one with the smaller moment of inertia. I for a solid cylinder of the same radius and mass as the hoops is larger, so it would go down faster. I for the solid cylinder is 1/2*M*R^2 and I for the hoops is just M*R^2.
Right. The one with the smallest rotational inertia per unit mass would win. (Note: It doesn't depend on mass or radius as long as the object rolls without slipping.)
If the moment of inertia of the cube were greater than the cylinder, would it reach the bottom second?
Cubes don't roll very well. :wink:
 
Doc Al said:
Cubes don't roll very well. :wink:

You should use a tetraheder ; it eliminates one bump :biggrin:
 
vanesch said:
You should use a tetraheder ; it eliminates one bump :biggrin:

How about an icosahedron so the bumps are smaller? :wink:
 
This has been discussed many times on PF, and will likely come up again, so the video might come handy. Previous threads: https://www.physicsforums.com/threads/is-a-treadmill-incline-just-a-marketing-gimmick.937725/ https://www.physicsforums.com/threads/work-done-running-on-an-inclined-treadmill.927825/ https://www.physicsforums.com/threads/how-do-we-calculate-the-energy-we-used-to-do-something.1052162/
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