Indefinite integral and anti-derivative

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Homework Statement



Find the indefinite integral of 16x^2+36+1/(16x^2+36) with respect to x


Homework Equations



Anything possible to take an anti-derivative

The Attempt at a Solution



I have absolutely no idea on how to deal with this problem. I can take an anti-derivative of the first 2 terms just fine but that fraction term just messes with me. I don't know how to take it on. It kind of looks like 1/(1+x^2) which would have an anti-derivative of arctan(x) but I really don't know how to handle this.

Thanks for the help:smile:
 
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If it looks like 1/(1+x^2), then maybe you should make it look more like such by factoring things out, and do a trig substitution.

Also, have you tried using partial fractions?
 
I've tried a bunch of ways to try to solve this. Of my whole homework set, this is the only one I can't get. I just don't see how to break apart that fraction.
 
You can't break apart that fraction. You need to make it look like 1/(a^2 + u^2), which has an antiderivative of arctan(u/a) + C.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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