Indefinite integral

use this identity:

[tex]
sin u = \frac{e^{iu}-e^{-iu}}{2i}
[/tex]

edit:
expand the sine in term of exponential, multiply them and regroup them into 2 cosine, then do the integral

 

use

[tex] \sin{\alpha}\sin{\beta} = \frac{\cos(\alpha-\beta) - \cos(\alpha + \beta)}{2}[/tex]

ehild

 

actually, my way is much much much more easier than remember you formulas.....
I can eye ball the answer using my way......
the answer is....
1/14 sin7x - 1/50 sin25x
the expansion of the complex number is easy.... there are only 4 terms