Indefinite Integration of 1/(3√x^2): Solving for x

draotic
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Homework Statement


1 / (3√x2 )


Homework Equations





The Attempt at a Solution


the overall power of x in denom becomes ( 1/2 * 2 * 1/3 = 1/3)
taking in num , it becomes (-1/3 + 1 = 2/3) so answer should be x2/3 / (2/3)
which is wrong , please help
 
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draotic said:

Homework Statement


1 / (3√x2 )

Homework Equations



The Attempt at a Solution


the overall power of x in denom becomes ( 1/2 * 2 * 1/3 = 1/3)
taking in num , it becomes (-1/3 + 1 = 2/3) so answer should be x2/3 / (2/3)
which is wrong , please help
\displaystyle \frac{1}{\sqrt[3]{x^2}\,}=\frac{1}{x^{2/3}}=x^{-2/3}

\displaystyle -\frac{2}{3}+1=\frac{1}{3}
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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