QuarkCharmer
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Homework Statement
A particle is moving with the given data. Find the position of the particle.
a(t)=t^{2}-4t+6,
s(0)=0,
s(1)=20
Homework Equations
The Attempt at a Solution
a(t)=t^{2}-4t+6, s(0)=0, s(1)=20
v(t)=\int t^{2}-4t+6 dt
v(t)=\frac{t^{3}}{3}-2t^{2}+6t+C_{1}
Then I suppose I take the antiderivative again to get to s (distance), I can't solve for the constant yet.
s(t)=\int \frac{t^{3}}{3}-2t^{2}+6t+C_{1} dt
s(t)=\frac{t^{4}}{12}-\frac{2t^{3}}{3}+3t^{2}+C_{1}t+C_{2}
So now I have two constants in there? Would I just use the parameters s(0)=0 and s(1)=20 to try to solve this like a system of 2 equations with two unknowns? I don't really know how to proceed. The other problems like this at least gave me a value for the first derivative of the original function so I could sort of work backwards.
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