Independent Events: Pr(A$\cap$B) = Pr(A)Pr(B)

sara_87
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My teacher gave these notes:

In general, if any two events A and B we find that Pr(B|A)=Pr(B), or equivantly,
Pr(AnB)=Pr(A)Pr(B),

then the events A and B are independent.



but i thought that when A and B are independent then Pr(AnB)=0?
what is my teacher trying to say, have i misunderstood something?
(btw n represents intersection)
 
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P(A intersect B) = 0 means they're disjoint. Disjoint events are almost never independent. (If you have knowledge that A happened, you're certain that B didn't happen, so the two events cannot be independent)
 
P(A and B)= P(A) P(B) means they are "independent". P(A and B)= 0 means they are "mutually exclusive": it one happens, the other can't. That's certainly not independent!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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