Index of refraction question-.

Thread starter AlanxD
Start date May 31, 2007
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Index Index of refraction Refraction

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To find the index of refraction of a convex lens with a focal length of 34.2 cm and radii of curvature of 30.0 cm and 40.0 cm, the lens maker's formula is applied: 1/f = (n-1)(1/R1 + 1/R2). Rearranging the formula allows for the calculation of the index of refraction (n). The resulting value indicates the type of glass used for the lens. The discussion emphasizes the importance of accurately applying the lens maker's formula for determining optical properties.

May 31, 2007

AlanxD

Suppose a convex lens is ground so that one surface has a radius of curvature of 30.0 cm and the opposing surface has a radius of curvature of 40.0 cm. The focal length is 34.2cm. What is the index of refraction of the lens? What kind of glass is the lens?

Need help by using the formula
1/f=(n-1)(1/R1+1/R2).

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May 31, 2007

AlanxD

oops nvm. Lemme repost.

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