Induced EMF from moving conducting rod

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SUMMARY

The discussion centers on the concept of induced electromotive force (EMF) generated by a moving conducting rod within a uniform magnetic field. The scenario involves two horizontal rails connected by a resistor and a conducting rod that slides on these rails. The key conclusion is that the magnetic field produced by the induced current is negligible compared to the external magnetic field directed into the page, which is crucial for understanding the direction of the resisting force acting on the rod.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with the Hall Effect
  • Knowledge of magnetic fields and forces on current-carrying conductors
  • Basic principles of circuit analysis involving resistors
NEXT STEPS
  • Study Faraday's Law and its applications in induced EMF scenarios
  • Explore the Hall Effect and its implications in electromagnetic systems
  • Learn about the interaction between magnetic fields and current-carrying conductors
  • Investigate circuit analysis techniques for understanding resistor behavior in electromagnetic contexts
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Students and educators in physics, electrical engineers, and anyone interested in the principles of electromagnetism and circuit behavior in the presence of magnetic fields.

OhBoy
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Homework Statement


Lets say we have two horizontal rails connected by a resistor to the left, and we have a movable conducting rod that slides without friction on the rails.There is a uniform magnetic field going into the page.

Homework Equations


F = ILB[/B]

The Attempt at a Solution


Now, I know that if the rail moves to the right with a velocity v, then Hall's effect shows that there will be an induced emf, and the resistor will draw a current. Now there should be a resisting force to stop the rod from moving but I'm not sure where the force comes from. If there is a current going counter clockwise, the current through the bridge will provide its own magnetic field going out of the page. Now, going back to the rod, current is moving up, field from bridge out of the screen, that makes the force going towards the right, not the left to resist the velocity. Do I use the field into the pay because it will (always?) be stronger than one produced by current through resistor? That would make the force to the left. I just want to make sure I have a conceptual understanding of where this force comes from.

So what am I doing wrong? Where is the resisting force derived when a force goes into move the conducting rod?
 
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OhBoy said:
Do I use the field into the pay [page] because it will (always?) be stronger than one produced by current through resistor? That would make the force to the left. I just want to make sure I have a conceptual understanding of where this force comes from.

Yes, in this situation it is generally assumed that the field produced by the induced current is negligible compared to the fixed external field (directed into the page).
 
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