1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Inductor in simple circuit w/ graph Problem Help

  1. Mar 21, 2008 #1
    1. The problem statement, all variables and given/known data
    In Figure 30-63, the inductor has 26 turns and the ideal battery has an emf of 16 V. Figure 30-64 gives the magnetic flux through each turn versus the current i through the inductor. If switch S is closed at time t = 0, at what rate di/dt will the current be changing at t = 1.9L?
    Figure 30-63 is a simple circuit with a battery, resistor, switch, and inductor.
    Figure 30-64 is a flux vs. current graph, with a constant slope of 2E-4H.

    2. Relevant equations
    L= flux/ current
    emf = L|di/dt|
    emf = |d(flux)/dt|

    3. The attempt at a solution
    I am rather lost. The graph shows flux per turn over current, but how do I know what the flux of each turn is? The graph is just an increasing slope with seemingly no boundries. Also, isnt the slope just (d(flux)/dt)/(di/dt)? And if so, wouldnt (di/dt) just be 1, or have I forgotten how to read graphs? Thanks for any help.
  2. jcsd
  3. Mar 21, 2008 #2
    I can't see any pictures
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook