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Industrial Electronics

  1. Apr 19, 2012 #1

    Femme_physics

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    Last edited by a moderator: May 5, 2017
  2. jcsd
  3. Apr 19, 2012 #2

    I like Serena

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    Luckily by now you can create your own solutions.

    I approve.
     
  4. Apr 19, 2012 #3

    Femme_physics

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    Ah... Great. Looks like I am on the top of my game! Thanks ILS.
     
  5. Apr 20, 2012 #4

    Ouabache

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    Yes, method & solutions look fine, nice job! Cool handles on your omega :smile:
    As a double check on part 2, you could also use
    [itex]P = I^2R[/itex] on the secondary circuit and solve for R.
     
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