Inelastic car collision, answers aren't matching up

AI Thread Summary
In a discussion about an inelastic car collision, a user initially calculated the final velocity incorrectly by adding the momentum of two cars traveling in opposite directions. After realizing the need to subtract the velocities due to their opposing directions, the user corrected the calculation. The correct final velocity of the combined mass post-collision is 3.33 km/h due east. This highlights the importance of considering directional components in momentum problems. The user successfully resolved their confusion with guidance from the forum.
BananasAreCool
Messages
3
Reaction score
0

Homework Statement


Car A, having a mass of 1.30 x 10+3kg is traveling at 60.0 km/h due east when it collides with car B, having a mass of mass 1.70 x 10+3kg traveling at 40.0 km/h due west. If the collision is totally inelastic, find the final velocity of car B.
.

Homework Equations


I'm using the equation
m1v⃗ 1+m2v⃗ 2=(m1+m2)vf

The Attempt at a Solution


I'm getting 146,000 = (3000)Vf which I'm then dividing to get a velocity of 48.66. But the answer key is telling me 3.33km/h due east. I haven't taken physics in years and am super rusty so any help would be much appreciated.
 
Physics news on Phys.org
Hi BananasAreCool, Welcome to Physics Forums.

Did you take into account the fact that the cars are traveling in opposite directions?
 
gneill said:
Hi BananasAreCool, Welcome to Physics Forums.

Did you take into account the fact that the cars are traveling in opposite directions?

That's what I was thinking was the problem, what is the equation for them moving in opposite directions?
 
BananasAreCool said:
That's what I was thinking was the problem, what is the equation for them moving in opposite directions?
I was just able to figure it out, I had to subtract instead of add the two so instead of getting 146,000 I got 10,000, which divided by 3,000 equals to 3.33km/h.
 
BananasAreCool said:
I was just able to figure it out, I had to subtract instead of add the two so instead of getting 146,000 I got 10,000, which divided by 3,000 equals to 3.33km/h.
Yup. Well done.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top