Infinite Ladder Network: Find R with Rs=1 ohm and Rp=6 ohms

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The discussion centers around calculating the input resistance of an infinite ladder network of resistances, specifically a repeating pattern of Rs (1 ohm) and Rp (6 ohms). The key equation derived for the input resistance R between terminals A and B is x = 1 + 1/(1/6 + 1/x), which leads to the conclusion that R(A-B) equals 3 ohms. The problem is noted for its elegance, showcasing the mathematical beauty of infinite series in electrical circuits.
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The http://www.his.com/~mhtesler/Ladder[/PLAIN] Network4.jpg]network shown (<—click on this link) is an infinite ladder of resistances (i.e., the “L-section” pattern of Rs and Rp resistances repeats indefinitely towards the right).

Let

Rs = 1 ohm

and

Rp = 6 ohms.

What is the input resistance R (i.e., the resistance between terminals A and B)?
 
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R(A-B) = 3 ohms ?
 
Gokul43201 said:
R(A-B) = 3 ohms ?

I agree with Gokul

it is an elegant problem

x = 1 + \frac{1}{1/6 + 1/x}
 
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