Infinite series sum is positive

myname1234
Messages
2
Reaction score
0
I was trying to prove the following but couldn't succeed. Is there a systematic methods to prove that the following infinite sum is positive? (alternating series)

sum from n = 0 to ∞ of ((-1)^{n}* x^{n+z}) / (n+z)!

conditions x≥0 and z≥1


note: when x≤1, we can directly see that s_{n}- s_{n+1} is positive for n ≥ 0. So the sum is positive.

However when x>1, s_{n} = x^{n+z} / (n+z)! monotonically increases first and then monotonically decreases to zero.
 
Physics news on Phys.org
Conditions for the sum of alternating series are:
1. alternating
2. ingnoring signs the function is decreasing
3. the limit of the f(x) as x approaches infinity is 0.

Just by looking at the problem you don't use the alternating series test. You have to use the Ratio Test and find the interval of convergence.
 
sorry, but i am not looking whether the series is converging or not. I know it converges.

Also your condition number 2 is not necessary for an alternating series to converge.

I am interested in proving that the total sum is positive.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top