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(a) Obtain the ground state wave function and energy. Draw the wave function
\psi_{1}(x)
(how many nodes are there in the ground state?) and the probability
\left | \psi_{1}(x) \right |^{2}
of finding the particle in dx about x.
V(x)=\begin{cases}<br /> & \infty,\text{ }x \geq a, x\leq -a \\ <br /> & 0,\text{ } -a< x< a <br /> \end{cases}
I've found the ground state wave function and energy to be:
\psi_{1}(x)=\sqrt{\frac{1}{a}}sin(\frac{\pi}{a}x)
E_{1}=\frac{\hbar^{2}\pi^{2}}{2m}
I'm not quite sure what is meant by "and the probability \left | \psi_{1}(x) \right |^{2} of finding the particle in dx about x."
Are they literally asking for \left | \psi_{1}(x) \right |^{2}or are they looking for an integral such as:
\int_{x-dx}^{x+dx}\left | \psi_{1}(x^{'}) \right |^{2}dx^{'}
\psi_{1}(x)
(how many nodes are there in the ground state?) and the probability
\left | \psi_{1}(x) \right |^{2}
of finding the particle in dx about x.
V(x)=\begin{cases}<br /> & \infty,\text{ }x \geq a, x\leq -a \\ <br /> & 0,\text{ } -a< x< a <br /> \end{cases}
I've found the ground state wave function and energy to be:
\psi_{1}(x)=\sqrt{\frac{1}{a}}sin(\frac{\pi}{a}x)
E_{1}=\frac{\hbar^{2}\pi^{2}}{2m}
I'm not quite sure what is meant by "and the probability \left | \psi_{1}(x) \right |^{2} of finding the particle in dx about x."
Are they literally asking for \left | \psi_{1}(x) \right |^{2}or are they looking for an integral such as:
\int_{x-dx}^{x+dx}\left | \psi_{1}(x^{'}) \right |^{2}dx^{'}