Infinite square well, Probability of measurement of particle's energy

machofan
Messages
8
Reaction score
0

Homework Statement



gHOY1oq.png


Homework Equations





The Attempt at a Solution



I have managed to do the first 3 parts of the questions. The last two 4 markers are the ones I am having difficulties with. I have tried using the expansion postulate which states the wavefunction is equal to the sum of the expansion coefficent "a" and the eigenfunction. Then by squaring the expansion coefficient, this should provide the probability.

The wavefunction from part 3) was found to be 2Acos(kx), and I've tried integrating this by squaring it, but I notice that's not the right way to go about this problem.

Any help would be much appreciated.
 
Physics news on Phys.org
As you said, the wavefunction Φ may be expanded in terms of a linear combination of the ψ(n). The {ψ} form an orthonormal basis. What happens if you take <ψ(1)|Φ>?
 
tman12321 said:
As you said, the wavefunction Φ may be expanded in terms of a linear combination of the ψ(n). The {ψ} form an orthonormal basis. What happens if you take <ψ(1)|Φ>?

If you take ψ and Φ, then integrate from a to -a, would that provide the expansion coefficient a_{n}? In which case, by squaring this coefficient, this would provide the probability?
 
This is a basic fact in quantum mechanics. You should consult your textbook so that you understand this, because you are bound to see it over and over again.
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top