Infinite Wire/Surface charge question

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The discussion centers on a physics problem involving an infinite wire with linear charge density near an infinite conducting surface. Key points include the need to sketch the charge configuration, electric fields above the plane, and the relationship between the electric fields from the wire and its image charge. The total electric field is derived to point in the negative z-direction, and the surface charge density on the conducting surface is shown to vary with position. The final goal is to confirm that the total charge on the surface matches the image charge's linear density, which is crucial for solving part (g) of the problem.
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Homework Statement


A thin infinite wire with linear charge density λ is located parallel to an infinite conducting surface, which is coincident with the x-y plane (i.e., z = 0). The wire is parallel to the ˆx direction and is located a distance z = d from the conducting surface. The figure on the left shows a section of the infinite wire and infinite surface in 3D, while the figure on the right shows the configuration projected in the y-z plane, where the wire is going into/out of the page.

(a) Sketch the location and charge configuration of the image charge.
(b) Sketch the total electric field E~ for region above the plane (z > 0).
(c) At a point located on the conducting surface ~r = (x, y, 0), sketch the electric field vector E~wire due to the charged wire. At the same point, sketch the electric field vector E~ image due to the image charge. Argue that the total electric field E~ = E~wire + E~ image points in the −zˆ direction.
(d) How are z-components of E~wire and E~ image related to each other?
(e) Determine the total electric field E~ at an arbitrary point ~r = (x, y, 0) on the surface. Your answer should depend on y and other constants given above. Hint: You just need to compute the z-component of E~wire, using your arguments in parts (c) and (d).
(f) What is the surface charge density σ on the conducting surface? (Note: The surface density is not constant; your answer should be a function of position y.) Sketch your answer for σ(y) as a function of y. (3 points)
(g) The amount of charge on the conducting surface must be the same as that of the image charge. Verify that the linear charge density of the surface charge along the x-direction, which is given by ∫ ∞ −∞ dy σ(y), (1) is the same as the linear charge density −λ of your image charge. (3 points)

Homework Equations


Field due to infinite wire: E=λ/2πε0r*cosθ

E = σ / ε0

Et = - (Eimage+ Ewiire)
Et = - λ/πε0r*cosθ

r=√(d2+y2)
cosθ = d/√(d2+y2)

σ = λ/πr3/2

The Attempt at a Solution


https://drive.google.com/file/d/0B76TBRMyBuffYzdZYUpVUk8zdkU/view?usp=sharing I only really need help with part g) I'm obviously doing something wrong as I either get 0 or an indefinite... Not quite sure what I"m doing wrong.
 
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The power of 3 on the right side is incorrect.
 

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It would be that easy...

Thanks a lot.
 
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