- #1

- 3

- 0

**Question:**

Find y as a function of x:

x^2 y'' + 8 x y' - 18 y = x^8

y(1)=3, y'(1)=2

**Attempted solution:**

I found the general equation to be Ax^(-9)+Bx^2+Cx^8.

However when I try to solve the initial value problem for this equation I have 3 unknowns.