- #1
gkchristopher
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(t+1) dx/dt = x^2 + 1 (t > -1), x(0) = pi/4
I have attempted to work this by placing like terms on either side and then integrating.
1/(x^2 + 1) dx = 1/(t + 1) dt
arctan x = ln |t + 1| + C
x = tan (ln |t + 1|) + C
pi/4 = tan(ln |0 + 1|) + C
pi/4 = C
x = tan (ln |t + 1|) + pi/4
Is this even close??
This was supposed to be a partial fractions exercise but I'm not seeing how. Thanks for any help.
I have attempted to work this by placing like terms on either side and then integrating.
1/(x^2 + 1) dx = 1/(t + 1) dt
arctan x = ln |t + 1| + C
x = tan (ln |t + 1|) + C
pi/4 = tan(ln |0 + 1|) + C
pi/4 = C
x = tan (ln |t + 1|) + pi/4
Is this even close??
This was supposed to be a partial fractions exercise but I'm not seeing how. Thanks for any help.