# Initial value problem

1. Sep 10, 2009

### -EquinoX-

Last edited by a moderator: May 4, 2017
2. Sep 10, 2009

### lanedance

is there a question?

also I would outline your initial assumption to help, and as a start look at putting a constant through your DE

3. Sep 10, 2009

### -EquinoX-

yes the question is here:

http://img40.imageshack.us/img40/7032/48975587.jpg [Broken]

Last edited by a moderator: May 4, 2017
4. Sep 10, 2009

### gabbagabbahey

If $m(m+9)(m+1)=0$, $=m-1$ and $m=-9$ aren't the only possible values of $m$ are they?

5. Sep 10, 2009

### -EquinoX-

yes, but web assign for some reason won't accept that answer

6. Sep 10, 2009

### gabbagabbahey

You have a cubic equation, so there should be 3 roots....you've only listed two of them...

7. Sep 10, 2009

### -EquinoX-

what's the other one? m = 0?

8. Sep 10, 2009

Yep.