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Initial value problem

  1. Sep 10, 2009 #1
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Sep 10, 2009 #2

    lanedance

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    is there a question?

    also I would outline your initial assumption to help, and as a start look at putting a constant through your DE
     
  4. Sep 10, 2009 #3
    yes the question is here:

    http://img40.imageshack.us/img40/7032/48975587.jpg [Broken]
     
    Last edited by a moderator: May 4, 2017
  5. Sep 10, 2009 #4

    gabbagabbahey

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    If [itex]m(m+9)(m+1)=0[/itex], [itex]=m-1[/itex] and [itex]m=-9[/itex] aren't the only possible values of [itex]m[/itex] are they?:wink:
     
  6. Sep 10, 2009 #5
    yes, but web assign for some reason won't accept that answer
     
  7. Sep 10, 2009 #6

    gabbagabbahey

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    You have a cubic equation, so there should be 3 roots....you've only listed two of them...
     
  8. Sep 10, 2009 #7
    what's the other one? m = 0?
     
  9. Sep 10, 2009 #8

    gabbagabbahey

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