Initial Velocity: Kinemetic Equations | When is 0 m/s OK?

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Initial velocity can be assumed to be 0 m/s when an object is "released from rest," meaning it has no initial motion. In the case of a football kicked straight up, the initial velocity is not zero because it has a velocity the moment it leaves the kicker's foot. The problem specifies the ball's flight time of 3.8 seconds, which can be used in kinematic equations to determine the initial vertical velocity. By using the equation for vertical position, one can solve for the initial velocity based on the time of flight. Understanding when to assume an initial velocity of zero is crucial for solving kinematic problems accurately.
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I just have a general question. When is it okay to assume that Initial Velocity is 0 m/s?

For instance I have this question:
A football is kicked straight up into the air; it hits the ground 3.8s later.

Do I assume that the initial Velocity is 0 m/s? Or do I assume that I'm only concerned at the point the football has left the kickers foot at which point it would have a velocity.
 
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\vec{}If you are concerned with the point the football has left the kicker's foot, it will have a nonzero velocity. If it did not, then it would stay on the ground where it was.

The problem gives you the additional information that the ball is in flight for 3.8 seconds. You can use this information in your kinematic equation for the vertical component of position:
y_{f} = y_{i} + v_{0y}t - \frac{1}{2}g t^{2}

Given that the initial and final height are both zero,
0= v_{0y}t - \frac{1}{2}g t^{2}
and you can plug in the time of flight (3.8s) to find the vertical component of the initial velocity v_{0y}.

Hope this helps:)
 
Generally, the problem will tell you if something is "released from rest", at which point, you are free to assume that the initial velocity is zero.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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