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a. if the ball has constant acceleration of -0.23 m/s^2, what is its velocity after 2.2 s?

V = vo + at = -1.5

-0.23 * 2.2 = -1.5 - 0.506 = -2.006 = -2.0 m/s

answer is -2.0 m/s

b. what was its average velocity during that time interval?

Vav = ( -2.0 - 1.5)/2 = -1.75 m/s

answer is -1.75 m/s

c. How far did it travel in this time interval?

D = VoxT + at^(2/2) = -1.5 * 2.2 - (0.23 * 2.2^2)/2 = -3.3 - 0.56 = -3.86

answer is -3.86