Initial velocity of rolling ball

[Siraaj]

A rolling ball has an initial velocity of -1.5 m/s .

a. if the ball has constant acceleration of -0.23 m/s^2, what is its velocity after 2.2 s?

V = vo + at = -1.5
-0.23 * 2.2 = -1.5 - 0.506 = -2.006 = -2.0 m/s
answer is -2.0 m/s

b. what was its average velocity during that time interval?
Vav = ( -2.0 - 1.5)/2 = -1.75 m/s
answer is -1.75 m/s

c. How far did it travel in this time interval?
D = VoxT + at^(2/2) = -1.5 * 2.2 - (0.23 * 2.2^2)/2 = -3.3 - 0.56 = -3.86
answer is -3.86

 

[scottdave]

This is from 2007. I'm not sure why it is popping up now... The OP has answered its own questions. It looks correct except for a misplaced parenthesis in part c: at^(2/2) should be a(t^2)/2 and correct units would be helpful.

 

[kuruman]

This is from 2007. I'm not sure why it is popping up now... The OP has answered its own questions. It looks correct except for a misplaced parenthesis in part c: at^(2/2) should be a(t^2)/2 and correct units would be helpful.

Most likely a bot caused it to pop up in its never ending quest for unanswered threads. Answering it will take it off the list and the thread will be relegated back to obscurity.