MHB Initial vertical velocity (vertical motion)

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The discussion focuses on deriving the equation for the height of a cricket that jumps with an initial vertical velocity of 4 ft per second. The relevant formula to use is y = y0 + v0y*t - 16t^2, where y0 is the initial height and v0y is the initial vertical velocity. Participants are encouraged to use this formula to write the height function and determine when the cricket lands back on the ground. The conversation emphasizes understanding the application of the formula rather than solving the problem outright. This approach aids in grasping vertical motion concepts in physics.
averyjedwards2
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hi there! i can't quite recall the formula for vertical velocity and who to easily factor the polynomials. Help anyone?
here's my example problem:
A cricket jumps off the ground with an initial vertical velocity of 4 ft per second.
A. write an equation that gives the height (in feet) of the cricket as a function of the time (in seconds) since it jumps.
B. after how many seconds does the cricket land on the ground?

thank you! i don't want you to necessarily solve this for me, i just need a little bit of a prompt with how to solve this! thanks so much!
 
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So you can use $y=y_0+v_{0y}t-16t^2$, where $y_0$ is the initial height, and $v_{0y}$ is the initial velocity in the $y$ direction. Can you proceed from here?
 
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