MHB Initial vertical velocity (vertical motion)

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SUMMARY

The discussion focuses on calculating vertical motion using the formula for height as a function of time. The initial vertical velocity of the cricket is specified as 4 ft/s. The equation to determine the height is given by the formula \(y = y_0 + v_{0y}t - 16t^2\), where \(y_0\) is the initial height and \(v_{0y}\) is the initial vertical velocity. Participants are encouraged to use this formula to derive the height function and determine the time until the cricket lands on the ground.

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averyjedwards2
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hi there! i can't quite recall the formula for vertical velocity and who to easily factor the polynomials. Help anyone?
here's my example problem:
A cricket jumps off the ground with an initial vertical velocity of 4 ft per second.
A. write an equation that gives the height (in feet) of the cricket as a function of the time (in seconds) since it jumps.
B. after how many seconds does the cricket land on the ground?

thank you! i don't want you to necessarily solve this for me, i just need a little bit of a prompt with how to solve this! thanks so much!
 
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So you can use $y=y_0+v_{0y}t-16t^2$, where $y_0$ is the initial height, and $v_{0y}$ is the initial velocity in the $y$ direction. Can you proceed from here?
 

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