Inner product generated by matrix

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SUMMARY

The inner product generated by the matrix [[1, 2], [-1, 3]] for vectors u = (-1, 2) and v = (2, 5) was calculated incorrectly in the forum discussion. The correct inner product is defined as = Au . Av, which should include cross terms u1v2 and u2v1. The distance d(u, v) was computed as abs(u - v) resulting in a value of 3 times the square root of 13, contrasting with the incorrect calculation yielding square root of 135.

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derryck1234
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Homework Statement



Find d(u, v), where the inner product is defined by the matrix

[1 2]
[-1 3]

and u = (-1, 2), v = (2, 5)

Homework Equations



<u, v> = Au . Av
d(u, v) = abs(u - v)

The Attempt at a Solution



I first tried to find the resulting inner product from the matrix in terms of an equation:

I got it to be:

2u1v1 + 13u2v2

Then I simply found u - v, which came to be (-3, -3)

And thus d(u, v) = <-3, -3>0.5

This, in terms of the relevant inner product, is:

[2(9) + 13(9)]0.5

Unfortunately, the books answer does not agree? It says it is 3 times root 13. I get root 135?
 
Physics news on Phys.org
Check your inner product calculation. There should be some u1v2 and u2v1 terms
 
Thanks.
 

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