Input and output voltages of a transformer?

AI Thread Summary
The discussion focuses on understanding transformer voltage and turn ratios, specifically the relationship between input and output voltages and coil turns. The formula Vo/Vi = No/Ni is highlighted, where Vo is the output voltage, Vi is the input voltage, No is the number of turns in the output coil, and Ni is the number of turns in the input coil. A practical example is provided, where a generator produces 24,000 V, and a transformer steps it up to 345,000 V with 2,000 turns in the input coil. Participants clarify how to apply the formula to find the required number of turns in the output coil. The conversation emphasizes the importance of understanding these concepts for solving transformer-related problems effectively.
derfrok
Messages
5
Reaction score
0
okay, I Don't quite grasp this concept but!. Vo/Vi = No/Ni.

And I have this problem. A Generator at a power plant produces AC at 24,000 V.A transformer steps this up to 345,000 V for transmission over power lines. IF there are 2000 turns of wire in the input coil of the transformer, how many turns must there be in the output coil? :biggrin:
 
Physics news on Phys.org
Heres how u do the problem...

First let me tell u the basics of a transformer. A transformer is a mutual inductance based device that transfers power from one part to the other. It does so by virtue of stepping up the voltage or the current.
i.e VI = constant. So if the input voltage, current and the number of turns are V1, I1 and N1 and those on the o/p are V2, I2 and N2, then,


N1*V1*I1 = N2*V2*I2 .

So, the voltage or current level can be stepped up or stepped down accordingly. Do u understand the concept now?

And about the solution to ur problem, I think u have answered ur qn. The answer is: Vin/Vout = Nin/Nout.


Sridhar
 
Yes, "Vo/Vi = No/Ni" . Also you are told that Vi= 24000, Vo= 345000 and Ni= 2000. Put those into the equation and you have:

345000/24000= No/2000. Can you solve for No?
 
ah! thanks guys.. see i thought i had the answer down! But, the tutors at my school we're telling me something else! Thanks for ellaborating! :biggrin:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top