Input Impedance of off center fed dipoles

AI Thread Summary
The discussion centers on the input impedance of off-center fed dipoles, particularly focusing on the formula for calculating radiation resistance based on distance from the feed point. It highlights that the standard half-wave dipole has an input impedance of 73 ohms when fed at the center, but this value changes when fed off-center. The importance of using a current balun to mitigate common mode currents and achieve better impedance matching is emphasized, especially when the antenna is designed for multiple bands. Participants note that the optimal height and length of the antenna significantly affect its performance, with specific recommendations for achieving desired impedance values. The conversation concludes with a call for further insights into optimizing antenna design and performance.
Jackson Richter
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My name is Jackson Richter. I am retired from Rockwell-Collins and worked in the engineering lab for 31 years. Since my retirement my interested have peaked in radio communications. Especially in antenna design. Thanks to anyone here that would give me a little more insight with my questions. The input impedance of a half wave dipole fed at the center in free space is 73 ohms with some reactance. I have been looking through a lot of data for a formula showing the input Impedance at various distances from the feed point. One in particular states from (Wikipedia)
Radiation resistance = 73.1/ sin squared(kx)
If the dipole is not driven at the center then the feed point will be higher. If the feed point is distance x from one end of the half wave (lambda/2) dipole, the radiation resistance relative to the feed point will be given by the above equation.
My question is if the feed point is at the center which is the 90 degree point, since a have wave dipole would be 180 degrees. then the sin of 90 =1 and K would also have to be 1 for this formula to work.
What is this value for K?

thanks JR

To be more exact the value for sin squared would have to be 1, for the 73 ohms to be valid in free space.
 
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Hello JR. Not sure what factor K is - it looks as if it should be 1 - but the formula looks approximately correct, assuming a sinusoidal current distribution. If feeding near to the end, the current distribution is not sinusoidal, as the impedance does not rise to infinity.
Also be aware that it is best to have the antenna a little shorter so it is resonant. This will improve the equality of the balance. It is also likely that a current balun or RF isolating transformer will be needed at the feedpoint to avoid common mode current on the feeder. The feeder may also require a second current balun some distance from the antenna. This is because with off-centre feeding, the feeder is not located at a neutral plane and will strongly pick up RF.
 
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Thanks so much for the info. Yes I know a current balan should be used at the feed point here. If a 4:1 balan is used at the feed point of approx. 33% of the over all length of 134ft. With a 4:1 balan then the impedances seen at different frequencies are around 120 ohms to 220 ohms. And this would equate to desirable impedance of around 50 ohms at the source input to the balan. And yes sir you are right this could cause some common mode currents on the 50 ohm source feed line. The current balan used if done professionally would offer some common mode rejection, haven't tested that out yet. With the formulas I suspect derived from Maxwell's theorems would allow to evaluate the feed point impedance at any position along the have wave antenna. That's where I am stuck, my friend the impedance equation should work for every degree on the half wave dipole. I am currently using this setup now very successfully and have worked many foreign station in my log, even with the band conditions being at its worst. So again thanks for your help.

JR
 
Be sure that the balun you are using is a current, not voltage, type.
It is also my thinking that at these frequencies, matching at the antenna is not the top priority because feeder loses with a Hi Z feeder are small. Matching can take place at the transmitter. The antenna needs to be chosen primarily to have the optimum radiation pattern in vertical and horizontal planes, and maximum gain in the desired direction(s).
 
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Thanks again for your input. Yes I am using a current balun ( sorry for the poor spelling in previous posts, hard to see screen) not a voltage type. The antenna is shaped like an inverted V with the apex about 44ft high. The great feature of this antenna, it is multiband and the Q is surprisingly low, making it broadband as well. Further investigating is needed for the input impedance at various distances from center of half wave dipole. Thank you again for your input

JR Richter
 
Sorry forgot to ask, What is the major difference between a current and voltage balun? A side from the fact that the current type will support higher currents and voltage type have higher insulating properties. I found that OCF antenna impedance is also dependent on height. Unlike the dipole that will target a 73 ohm value the higher it is. I believe it follows the dipole impedance vs height charts some what, only if the height is below half wave length. The optimal height according to others is 15 meters, which also sets the feed point impedance as well. Also the length found to optimal is 134 ft, targeting a frequency around 3.6 Mhz. The second harmonic falls on 7.2 and then 14.4 etc. Still wondering why this length works as well as it does. I am trying to equate everything here that I using as of today. I hoped to make sense of all of it and put it down on paper for proof. Thanks again for any help here.

JR Richter
 
For any length dipole I expect the radiation resistance will be a function of the distance in quarter wavelengths from the nearest maximum current node of the standing wave. The k in your equation will depend on the units used for x. At first sight I think k will only be 1, or π/2 when x is measured in quarter wavelengths. This might be a transmission line problem for solution on a Smith Chart.

I have no doubt that a dipole in free space has a neat equation for off-centre complex feed impedance, but that equation you are looking for is hypothetical once you are in the real world. There was a time when I was running portable 3.5MHz links from tall forests. I found the inverted V to be an excellent antenna. I modeled it numerically before building it, then found I could not improve the design by changing wirelength in the field. I always centre-fed the dipole because that was where the hoist up the tree and the feedline were best positioned to avoid tangles with other trees. The two arms of the dipole sloped down at an angle designed to optimise a one skip reflection to base, it was changed for different ranges. Tuning was dependent on ground conditions. I tuned the reactance by adjusting the height of the ends above the ground rather than trimming the wire length or transmatch, that also reduced feed-line losses.

Even with a centre fed inverted V, the length of the wire, the feed height and the end-ground effects all conspire to make it non-theoretical. As the V becomes steeper the ground reflection becomes more important in determining radiation pattern because low angle end-fire rather than dipole field begins to become significant.
 
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Jackson Richter said:
Sorry forgot to ask, What is the major difference between a current and voltage balun?

The voltage balun may be thought of as an RF transformer having a secondary which has a grounded centre tap and which is connected to the antenna. It will produce equal voltages on the two legs of the load, but the currents will differ if the legs have different impedances. It can also allow common mode currents (i.e. push-push currents) to pass unimpeded.
The current balun can be thought of as an RF transformer with an untapped floating secondary. It will force the current in the two legs to be equal no matter what their impedances are and will not allow common mode currents to pass.
 
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Yes your right, using the antenna like this in the real world compared to free space is difficult to pin down. I do believe though with that being said, a design parameter can be used to put this antenna system up with fairly good results. Most of the people using this technique are also having very good luck with higher efficiencies with their antenna systems. Again this is with a 4:1 balun 90ft on one leg and 44ft on the other. The balun is raised to 35 to 45 ft with the wires spread 180 degrees apart from each other and the ends of the wires are at least 15ft off the ground. Feeding this antenna with 50 ohm coax (half wave lengths) with a velocity factor (.666) very good results have been achieved. on 80 meters the lowest VSWR is around 3.7 Mhz. Across the ban the highest VSWR is 2 from one end of the band to the other. On 40 meters pretty much the same if now lower. etc.

I am trying to put all of this in a logical order with starting from the basic Lambda= speed of light(C)/ F (Mhz). to the wire size vs length for the k factor in this wavelength formula. Along with that why does this 134 length make sense or is there another length (on paper and real world) that would be better. The position of the feed point vs impedance along with height above ground would make a very good antenna system and also multiband as well.

So to Clarify:
1. Calculated half wave length used for OCF antenna? What is the optimal length for 80,40,20,10 and 6 meters
half wave (meters) =.5* k * 300/f(Mhz), 12awg wire the k factor is approx. equal to length (meters)/dia wire (meters)
41.7/.00202574 = 20,268
l/d ratio equates to .975 from charts
half wave (meters)= .5 *.975* 300/3.5
half wave (meters)= 41.7
half wave (feet) =136.8



k (harmonic) 1 at 80 meters x ( degrees where feed point is located) example below
2 at 40 meters x = 90 degrees if put in middle of dipole
3 at 20 meters x = 60 degrees when feed point is at 1/3 length of dipole (44ft point)
4 at 10 meters

2. Radiation resistance at feed point = 73/ sin squared ( kx) free space 3. Antenna height vs impedance : It is very apparent that this ocf antenna doesn't follow the standard dipole
input impedance vs height relationship. The standard dipole will target to 73 ohms
above 1 wave length. Where as the ocf impedance will continue to increase as the
height is increased. I assume that's why the recommended height is 15 meters,
to make the feed point 100 to 200 ohms. Again with the 4:1 balun this would bring
the impedance down to or close to 50 ohms, ideal for coax usage.

This antenna again is a multiband antenna, which makes it very nice to use. Its know also for being very flat across the bands on the different frequencies.
If anyone can find holes in this please advise. I know there are a lot of unknowns here especially feed line, soil data, and proximity etc. Also known is this antenna is very sensitive to metal objects around or near it. What I am trying to do is to approximate these solutions so as to make sense of this antenna
Thanks to all who might add to this. Also will respect any criticism.

JR Richter
 
  • #10
tech99 said:
The voltage balun may be thought of as an RF transformer having a secondary which has a grounded centre tap and which is connected to the antenna. It will produce equal voltages on the two legs of the load, but the currents will differ if the legs have different impedances. It can also allow common mode currents (i.e. push-push currents) to pass unimpeded.
The current balun can be thought of as an RF transformer with an untapped floating secondary. It will force the current in the two legs to be equal no matter what their impedances are and will not allow common mode currents to pass.

If that's the case, if a current balun was used in a dipole configuration with unequal lengths of wire on each side, would it still have the common mode rejection, assuming fed with unbalanced feed line.

Thanks for your response.

JR Richter
 
  • #11
Baluncore said:
For any length dipole I expect the radiation resistance will be a function of the distance in quarter wavelengths from the nearest maximum current node of the standing wave. The k in your equation will depend on the units used for x. At first sight I think k will only be 1, or π/2 when x is measured in quarter wavelengths. This might be a transmission line problem for solution on a Smith Chart.

I have no doubt that a dipole in free space has a neat equation for off-centre complex feed impedance, but that equation you are looking for is hypothetical once you are in the real world. There was a time when I was running portable 3.5MHz links from tall forests. I found the inverted V to be an excellent antenna. I modeled it numerically before building it, then found I could not improve the design by changing wirelength in the field. I always centre-fed the dipole because that was where the hoist up the tree and the feedline were best positioned to avoid tangles with other trees. The two arms of the dipole sloped down at an angle designed to optimise a one skip reflection to base, it was changed for different ranges. Tuning was dependent on ground conditions. I tuned the reactance by adjusting the height of the ends above the ground rather than trimming the wire length or transmatch, that also reduced feed-line losses.

Even with a centre fed inverted V, the length of the wire, the feed height and the end-ground effects all conspire to make it non-theoretical. As the V becomes steeper the ground reflection becomes more important in determining radiation pattern because low angle end-fire rather than dipole field begins to become significant.

When using the value for K you said that K could be 1 or pi/2. I assume pi is in radian measure. Later posts I tried k as a variable for bands such as 80m =1 and 40m=2, 20m=3. Just guessing here? probably way off the mark lol. So thank you again will try it out too. When drooping the ends of the antenna I assume your increasing the capacitance reactance. This antenna is super sensitive to objects around it, but works very well when put up properly. thanks again for your input
JR Richter
 
  • #12
Code:
Zo = 72 ohms
k = 2π / λ
x measured from nearest end of half wave dipole.
θ = k * x
R = Zo / ( Sin θ * Sin θ )

  Xposn  Rohms
  0.010 18261.8
  0.020  4583.5
  0.030  2050.6
  0.040  1164.2
  0.050   754.0
  0.060   531.3
  0.070   397.2
  0.080   310.2
  0.090   250.8
  0.100   208.4
  0.110   177.2
  0.120   153.6
  0.130   135.5
  0.140   121.3
  0.150   110.0
  0.160   101.0
  0.170    93.8
  0.180    87.9
  0.190    83.3
  0.200    79.6
  0.210    76.7
  0.220    74.6
  0.230    73.1
  0.240    72.3
  0.250    72.0
 
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  • #13
Jackson Richter said:
If that's the case, if a current balun was used in a dipole configuration with unequal lengths of wire on each side, would it still have the common mode rejection, assuming fed with unbalanced feed line.

Thanks for your response.

JR Richter
Yes
 
  • #14
Baluncore said:
Code:
Zo = 72 ohms
k = 2π / λ
x measured from nearest end of half wave dipole.
θ = k * x
R = Zo / ( Sin θ * Sin θ )

  Xposn  Rohms
  0.010 18261.8
  0.020  4583.5
  0.030  2050.6
  0.040  1164.2
  0.050   754.0
  0.060   531.3
  0.070   397.2
  0.080   310.2
  0.090   250.8
  0.100   208.4
  0.110   177.2
  0.120   153.6
  0.130   135.5
  0.140   121.3
  0.150   110.0
  0.160   101.0
  0.170    93.8
  0.180    87.9
  0.190    83.3
  0.200    79.6
  0.210    76.7
  0.220    74.6
  0.230    73.1
  0.240    72.3
  0.250    72.0

Thanks for your input here. Not sure what the x value is. Is it the % center, or x/lambda, degrees from lambda/2. Please clarify if you would, thanks

JR Richter
 
  • #15
Jackson Richter said:
Thanks for your input here. Not sure what the x value is. Is it the % center, or x/lambda, degrees from lambda/2. Please clarify if you would, thanks
Both λ and x are in metres. x is measured from the end of the half wave dipole.

Maybe I should have included these obvious initial lines.
MHz = 106
c = 299792458.
freq = 300. * MHz
λ = c / freq
Then generate the table by looping For x = λ/100 to λ/4 step λ/100

Since the example table was computed for 300MHz, where λ = 1 m, the example x was also in wavelengths.
If you change freq to 1 MHz, where λ = 300 metres, then R will still range from 18261 ohms to 72 ohms, but x will then range from x=2.998m to 74.948m.
 
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  • #16
Baluncore said:
Both λ and x are in metres. x is measured from the end of the half wave dipole.

Maybe I should have included these obvious initial lines.
MHz = 106
c = 299792458.
freq = 300. * MHz
λ = c / freq
Then generate the table by looping For x = λ/100 to λ/4 step λ/100

Since the example table was computed for 300MHz, where λ = 1 m, the example x was also in wavelengths.
If you change freq to 1 MHz, where λ = 300 metres, then R will still range from 18261 ohms to 72 ohms, but x will then range from x=2.998m to 74.948m.
Please remember that the current distribution is only approximately sinusoidal. If you feed the wire at the end, the impedance depends on the conductor diameter, but for a wire it may be 5000 ohms or so and not infinity. Also, resonance occurs when the length is a little less than half a wavelength.
 
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  • #17
tech99 said:
If you feed the wire at the end, the impedance depends on the conductor diameter, but for a wire it may be 5000 ohms or so and not infinity.
It is quite farcical to consider driving a dipole with a current source at the end of the dipole.

Ideally, the wire diameter of an inverted V antenna should be tapered in proportion to the distance from the ground. Where the wires approach the balun they should also taper towards the balun terminals. For narrow band HF that requires a cage dipole, but no one seems to acknowledge the advantage of that impedance matching these days.
 
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  • #18
Thank you for your input again. I know from the past that when a wire is end fed its called an end fed zep. A matching system must be used to match the output impedance from the transmitter and feed line to the input impedance of the wire antenna. Typically these antennas are multiple wave lengths long and have directivity when mounted the right distance off the ground. As far as the OCF antenna, I have read so many descriptions of the this antenna and no one is getting the same results, different equations, different lengths, different heights and different feed points across the 1/2 wave dipole. The height plays a very important factor for determining input impedance of this antenna. unlike the standard dipole that targets 73 ohms above 1 wave length. I am trying to validate data and put the results in sensible order and achieve the optimal feed point position to cover the maximum band usage along with proper height to achieve ground wave and single hop communications. Maybe a simple solution can't cover all the real world installations. I am trying to cover the basics so others can understand and add to the knowledge base of this particular antenna. I not saying others are wrong, but what I am saying, I just want to validate their findings with my data and experimentation. So thank you for your input.

JR Richter
 
  • #19
Baluncore said:
It is quite farcical to consider driving a dipole with a current source at the end of the dipole.

Ideally, the wire diameter of an inverted V antenna should be tapered in proportion to the distance from the ground. Where the wires approach the balun they should also taper towards the balun terminals. For narrow band HF that requires a cage dipole, but no one seems to acknowledge the advantage of that impedance matching these days.
I thought that the tapering would cause higher Q and lower bandwidth, making it a much narrower operating window for single frequency.
 
  • #20
Jackson Richter said:
I thought that the tapering would cause higher Q and lower bandwidth, making it a much narrower operating window for single frequency.
Once you tune a 3.5 MHz dipole with a Q of 100, you still have a bandwidth of 35 kHz.
 
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  • #21
Baluncore said:
It is quite farcical to consider driving a dipole with a current source at the end of the dipole.

Ideally, the wire diameter of an inverted V antenna should be tapered in proportion to the distance from the ground. Where the wires approach the balun they should also taper towards the balun terminals. For narrow band HF that requires a cage dipole, but no one seems to acknowledge the advantage of that impedance matching these days.
Baluncore said:
It is quite farcical to consider driving a dipole with a current source at the end of the dipole.

Ideally, the wire diameter of an inverted V antenna should be tapered in proportion to the distance from the ground. Where the wires approach the balun they should also taper towards the balun terminals. For narrow band HF that requires a cage dipole, but no one seems to acknowledge the advantage of that impedance matching these days.
Yes of course, no one would use a current balun at the end of the line.

Supposedly the optimal length of the antenna to be 134 ft and fed at the 1/3 the distance from the end. Using a 4:1 balun at this point. A construction practice is to connect a 90ft wire to one side of this balun and 44ft to the other side. When raised to a 15 metre (aprox.) height in an inverted V configuration. This antenna is used at (3.5 to 4 Mhz), ( 7 to 7.3 Mhz), (14 to 14.35Mhz), (28 to 28.7Mhz) and (50 to 54Mhz) with great success.

I currently have this antenna now and it works surprisingly well, I am not sure if this is the optimal configuration. The questions I have are:
What is the optimal length? What is the optimal height? What is the optimal feed point location? What is the optimal wire size? Currently I am using #12 awg silver stranded wire with Teflon coating for the wire lengths. The antenna appears to have a little lower noise floor while also reducing the IR losses, making the antenna a little more efficient.
 
  • #22
Baluncore said:
Both λ and x are in metres. x is measured from the end of the half wave dipole.

Maybe I should have included these obvious initial lines.
MHz = 106
c = 299792458.
freq = 300. * MHz
λ = c / freq
Then generate the table by looping For x = λ/100 to λ/4 step λ/100

Since the example table was computed for 300MHz, where λ = 1 m, the example x was also in wavelengths.
If you change freq to 1 MHz, where λ = 300 metres, then R will still range from 18261 ohms to 72 ohms, but x will then range from x=2.998m to 74.948m.

When using C / F(Mhz) to find length, this is for free space and doesn't take in account vf or Length vs diameter of conductor used. Shouldn't it be: k * speed of light/ F (Mhz). or appox or .975 * C/ F(Mhz). lambda (metres) = 292.3 / F(Mhz)?
 
  • #23
Jackson Richter said:
Shouldn't it be: k * speed of light/ F (Mhz). or appox or .975 * C/ F(Mhz). lambda (metres) = 292.3 / F(Mhz)?
The VF of bare copper wire is close to 99.7%, I once measured it because my computer model did not fit reality. But it depends slightly on the moisture content of the brown copper chemical surface which might be an acetate or an oxide. If you have insulation on the wire, then things will be slightly slower.

Jackson Richter said:
What is the optimal length? What is the optimal height? What is the optimal feed point location? What is the optimal wire size?
Optimal for what? The OSF inverted V is a messy antenna. The radiation patterns of the two legs make the pattern quite complex on the higher frequencies. Any big antenna works OK if you have propagation and a tuner.
Why do you use feet for the only thing that is related to the wavelength in metres.
90ft + 44ft = 134ft = 40.843 m = λ/2, λ = 81.686 so Freq = 3.67 MHz.

The impedance of the feedpoint will be different for every band since the distance from the nearest current maximum will be wavelength dependent. Is the 1/3 distance from the end measured along the wire or one of the legs? Is the feed at the top of the V or half way up the long leg? Maybe a picture with dimensions would help.
 
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  • #24
Yes, your right this is a messy antenna. There are a lot of variables. Different frequencies, different heights, different lengths. Also. I should maintain standard measuring lengths, thank you. Again the length used for this antenna is 40.843 m. The feed point is at 13.411m. The half wave length at 3.6 Mhz is 40.843 m. The second harmonic falls in the 40 m band, 4th harmonic falls on the 20 m band etc. And yes their impedances are different. But If a correct length is used a common impedance around 95 to 250 can be obtained. So far, 1/3 the length of the half wave seems to work very nicely. G80DE has done a lot of work on this but I am not sure if these is best lengths. With the 4:1 current balun, fed at this x length a multiband antenna can used effectivity. The point is to determine what the best length is supposed to be. Also, what is the optimal height to make this work and why. Maybe your right, maybe there is no pin point accuracy to all of this, but I have to try. Thanks again for your time.
 
  • #25
Baluncore said:
Is the 1/3 distance from the end measured along the wire or one of the legs? Is the feed at the top of the V or half way up the long leg? Maybe a picture with dimensions would help.
1/3 of the way along what? Measuered from which end? Where?
Jackson Richter said:
With the 4:1 current balun, fed at this x length a multiband antenna can used effectivity.
Because your feed-point has highly variable impedance over frequency, you will need an antenna matching unit at the balun to prevent circulating reactive current on the lossy coaxial feedline. Would you not be better using an open wire parallel transmission line which will have a better matched impedance with much lower losses than coax. You can then ignore the matching unit at the antenna by using a matching unit in the shack where it will be more accessible.
 
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  • #26
You will notice that the cheaper is the coax used for the feedline, the lower is the SWR. That is because the reflected wave is being absorbed twice by the cheap coax. When you use a balanced ladder-line you will begin to recognise the real SWR and so can see the mismatch of the antenna to the feedline. Eliminating the coax and balun is probably the single greatest improvement you could make to the performance and to your understanding of the antenna.
 
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  • #27
Baluncore said:
1/3 of the way along what? Measuered from which end? Where?

Because your feed-point has highly variable impedance over frequency, you will need an antenna matching unit at the balun to prevent circulating reactive current on the lossy coaxial feedline. Would you not be better using an open wire parallel transmission line which will have a better matched impedance with much lower losses than coax. You can then ignore the matching unit at the antenna by using a matching unit in the shack where it will be more accessible.

Open wire feed line is very low loss for sure. Its more difficult to work with and matching is definitely required at the transmitter site like you mentioned. When very long runs of feed line are needed, the two options are open wire feed or hard line. My particular situation, I running about 1/2 wave length feed line on 75 metres. You asked "1/3 length to what?" The feed point is located 1/3 length of 40.623metres which is 13.5 metres. The other leg is 27.123 metres. The over wave length is a 1/2 wave length at 3.6 Mhz which is 40.623 metres. Making a feed point impedance of 97.69 ohms, but when raised to a higher level the impedance also increases. Determining what over all height and feed point positions are my goal if at all possible. The rule in the past has been the 15 metre level. The question comes in about common mode currents? A well constructed 4:1 balun (unbalanced to balanced) high power, should reduce the common mode currents. Balun Design makes such a balun its 4114 ocf, rated at 5kw. Thanks again for your time and information.
 
  • #28
The more I consider your offset fed dipole, with a bend close to 90° at the feed point, the more unpredictable it becomes at the shorter wavelengths and the less like a dipole it appears to be at the longer wavelengths.

It might be better to analyse it as the sum of two random wires driven against two counterpoises.
 
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  • #29
Baluncore said:
The more I consider your offset fed dipole, with a bend close to 90° at the feed point, the more unpredictable it becomes at the shorter wavelengths and the less like a dipole it appears to be at the longer wavelengths.

It might be better to analyse it as the sum of two random wires driven against two counterpoises.

Well I guess that's the beauty of it. Yes it is a complicated antenna, but yet simplistic to build and works very well. I know you say compared to what? If I wanted to build a single antenna for one frequency then I wouldn't worry about all of this and design it by the book. If I had a huge area to put it on, or a tall tower or tall trees to hang it. We all don't have this option, but this is one antenna that has it all. It appears to be very efficient, even with the balun. It also is very broad band, with small deviation in VSWR across the bands. Its also a multiband antenna that works at the fundamental, 2nd, 4th, 8th harmonic of the original low band frequency, (if properly picked). I personally have heard many amateur stations change from being a weak station to strong station with this antenna. Yes sir you are right, analysis of this antenna would be my next step. I think there is still more to learn about this OCF antenna and possibly make it better. Thank you for your input.
 
  • #30
I was looking at a earlier study and I am frankly stumped. In the equation where we were looking at a certain feed point location on a half wave dipole and moving this location away from center, and plotting the different impedance values for the x distance from end of the antenna, works well for a single frequency. I am have trouble doubling the frequency and plotting the same impedance point. For instance; We know the impedance of a half wave dipole fed in the middle is about 73 ohms in free space. If we tried to use this same antenna, same feed point location, but double the frequency, what happens to the impedance? According to the prior study this impedance will be 4000 ohms. I agree that it will be hi, but not sure how to enter that in the equation below. It obvious that I don't understand the equation that you nicely showed in your explanation for impedance vs feed point location. I know this antenna only works on 2nd, 4th, 8th harmonics. Where does that fit into the equation if you change frequency and keep the same original length? Is that just a multiplier of the angle?

Rr = 73 / Sin squared ( 2 * pi * X/ lambda)

where x = location ratio to lambda (if at center of half wave antenna) = .25
2 * pi = 360 degrees (if at center .25 * 360) = 90 degrees
sin of 90 = 1 and that squared is 1 in the denominator, which just leaves the numerator of 73.
Thanks for any help here
 
  • #31
It is not a dipole, it is not a multi-band antenna. It is an amateurs random wire against a counterpoise.
It cannot be modeled generally as it is highly dependent on ground and nearby structures.
It will work sometimes if you have a good antenna tuner.
 
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  • #32
Baluncore said:
It is not a dipole, it is not a multi-band antenna. It is an amateurs random wire against a counterpoise.

the best statement so far made in this thread :smile:

Jackson Richter said:
Well I guess that's the beauty of it. Yes it is a complicated antenna, but yet simplistic to build and works very well. I know you say compared to what? If I wanted to build a single antenna for one frequency then I wouldn't worry about all of this and design it by the book. If I had a huge area to put it on, or a tall tower or tall trees to hang it.

Hi Jackson

Have you considered a probably much better alternative ... a trapped dipole ?
They are great for multiband use. And you can please yourself if you use it as a flat ( horizontal )
dipole or as an inverted V. The inverted-V just gives a better non-directive radiation pattern than a horiz. dipole that you cannot rotate

EDIT: or if you don't like trap building ... go for a G5RV broad band antennaDave
 
  • #33
Thank you Dave for your input. I have considered many antennas for my projects. I do believe strongly that the antenna is the most important part of the communications process. With in the last year I have been using this OCF antenna. There are so many positive aspects about it. 1st, its very broad band. 2nd, its multiband. 3rd, it has a very flat VSWR across these bands. 4th, it actually blows the g5rv and others like it, out of the water. It appears to be a very efficient antenna. I talk to many others that have this same antenna, who sound strong and do much better now since they have changed to this antenna. So what I am trying to do is to quantify it and put the data in a form that makes it more predictable. I guess you would have to see for yourself, being from Missouri, lol. All kidding aside, There are a few quirks about this antenna that have to pinned down and analyzed. So with that being said, that's what I am trying to do. There are 4 things that make this antenna work. 1st, A very good current balun, designed for high power and built unbalanced to balanced configuration. (to help with common mode currents) and impedance matching. 2nd, This antenna is put in an inverted V configuration. 3rd, The height is also very important, because of the near field radiation. This antenna if mounted 30 to 40 ft high, the OCF input impedance falls within limits of the 4:1 balun and nicely transfers that impedance down to a proper value that output transmitter and coax can drive. 4th, This antenna must be clear of any large metal objects within the near field proximity. That's pretty much it. Sorry, I hope this makes sense to you. Seeing is believing and I should have tackled this antenna years ago. I talk every day on this antenna and have worked Europe on 20 meters many times even with the terrible band conditions. I also talk to California every night on 80meters with this antenna. Its like having a super nice car, you want to keep it fine tuned. I am also trying to fine tune the OCF as well.

Jackson WB0USA
 
  • #34
If you drive it at one end and place a terminating resistor at the other, it forms a half rhombic, or Bruce, antenna, and will have gain and F/B ratio for frequencies of about 14MHz upwards. It will also have a fairly uniform driving point impedance.
 
  • #35
Jackson Richter said:
I do believe strongly that the antenna is the most important part of the communications process.
You have a lot to learn. Without propagation, communication is impossible. With propagation, just about any antenna will work when tuned.

Jackson Richter said:
There are so many positive aspects about it. 1st, its very broad band. 2nd, its multiband. 3rd, it has a very flat VSWR across these bands.
If that flat VSWR is close to 1.0 then it indicates that you do not have a resonant antenna attached, you simply have high losses in your feedline, tuner and/or environment.

A dummy load also has a flat VSWR. It radiates in the IR band as heat. A low SWR may indicate that little energy is returning to the SWR meter because it is lost as heat before it gets back.
 
  • #36
Jackson Richter said:
I do believe strongly that the antenna is the most important part of the communications process.

Baluncore said:
You have a lot to learn. Without propagation, communication is impossible. With propagation, just about any antenna will work when tuned.

indeed

Jackson Richter said:
There are so many positive aspects about it. 1st, its very broad band. 2nd, its multiband.

There's so many negative ones too, as have been discussed in this thread, It's broad band. NOT multiband as you have already been told. And broadband immediately brings about very low gain compared to any other resonant antenna eg. a dipole. The OCF will never have the gain of a dipole on any given frequency.

Baluncore said:
If that flat VSWR is close to 1.0 then it indicates that you do not have a resonant antenna attached, you simply have high losses in your feedline, tuner and/or environment.

A dummy load also has a flat VSWR. It radiates in the IR band as heat. A low SWR may indicate that little energy is returning to the SWR meter because it is lost as heat before it gets back.

again agreed

Jackson Richter said:
actually blows the g5rv and others like it, out of the water. I talk to many others that have this same antenna, who sound strong and do much better now since they have changed to this antenna.

really ? ... when being compared to another antenna from the same location and transmitter ? I doubt it has been done

I wouldn't believe that statement till actual side by side tests were done ... hearsay isn't worth diddly squat :wink:

Jackson Richter said:
It appears to be a very efficient antenna

appears being the operative word

Jackson Richter said:
So what I am trying to do is to quantify it and put the data in a form that makes it more predictable.

Jackson Richter said:
Seeing is believing and I should have tackled this antenna years ago

that IS the ONLY way and as I said earlier, you cannot compare it to another antenna unless they are being used from the same location and with the same gear

DONT believe till you see actual results

Jackson Richter said:
I guess you would have to see for yourself, being from Missouri, lol. All kidding aside,

Ohhh, and I have probably traveled more highways and byways of Missouri and the other mid-western states than you :wink::wink:

Storm chasing takes you anywhere and everywhere :smile:
Dave
 
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  • #37
A beginner will claim perfection of a bent wire coat hanger if he QSLs the antipodes with 300 watts, on HF, just once. A professional will claim imperfection if they fail to communicate on one day in the year.
Nearby, more experienced amateurs will communicate with the antipodes daily, over a decade or more, with 1 watt QRP. They will not praise their antennas because it is the choice of the right band for the available propagation that really makes the real difference. They will use open wire feed lines with a transmatch and an antenna tuner.
 
  • #38
First of all, I don't clam to be a professional! Maybe I am over zealous on this antenna, because I hear it and use it EVERY DAY. I am reporting what I have observed. Yes you are right, the propagation has to be there to have consistent communication. Dave I am sorry but I haven't heard a good sounding G5RV yet. That doesn't mean there isn't one. I have also had others report the same thing about the G5RV. If it looks like a bad antenna, runs like a bad antenna, maybe it is a bad antenna. Pardon the expression "bad", There are a lot of antennas out there, some that WORK most of the time and some that work during good propagation "with 1 watt" and if your lucky get to another state. The real amateurs today know that the propagation is on a decline and probably won't get better for quite a few years, unlike the 50's and 60's where a watt of power could get you around the world. Yes changing bands to get the proper MUF has already around for years. Sorry If I offend anyone, that wasn't the intent. All I wanted to do was ask questions about an antenna that "appears" to work EVERY DAY! even when the propagation is poor. By the way Dave, we have a Dr.Gupta here in Cedar Rapids that is also a storm chaser and loves it.
I hope everyone has a good day.

JR Richter WB0USA
 
  • #39
,HI Jackson

Jackson Richter said:
First of all, I don't clam to be a professional!

Nor do I, tho I have worked in the telecommunications industry for the last 40 yrs

Jackson Richter said:
Maybe I am over zealous on this antenna, because I hear it and use it EVERY DAY. I am reporting what I have observed.

God forbid, I'm sure Baluncore and I definitely are not trying to squash your enthusiasm ... something that is severely lacking everywhere.
What we both are saying is, DONT let it override empirical science/testing :smile:

BUT have you actually, As I said in a previous post, tried it in a side by side comparison with any other antenna, where you just antenna switch between the two ?
probably not ... and that is where the real test comes

Jackson Richter said:
Dave I am sorry but I haven't heard a good sounding G5RV yet. That doesn't mean there isn't one. I have also had others report the same thing about the G5RV. If it looks like a bad antenna, runs like a bad antenna, maybe it is a bad antenna. Pardon the expression "bad",

The G5RV was just an example ... Any non-resonant antenna is a compromise and I doubt it's any better or worse than your OCF which is also a serious compromise. The G5RV works in that it provides wide band coverage for minimal construction effort

Jackson Richter said:
There are a lot of antennas out there, some that WORK most of the time and some that work during good propagation "with 1 watt" and if your lucky get to another state.

If it is a resonant system like a fixed band dipole, a trapped dipole, or a yagi. it will WORK, ALL the time and all else being equal, the ONLY thing that will affect operations will be the propagation. I can guarantee my trapped dipole will out-perform your OCF or a G5RV any day.

Jackson Richter said:
The real amateurs today know that the propagation is on a decline and probably won't get better for quite a few years, unlike the 50's and 60's where a watt of power could get you around the world

anyone in long haul telecoms does ... amateur or professional :wink:

Jackson Richter said:
Sorry If I offend anyone, that wasn't the intent.

there's been no offense anywhere :smile:

Jackson Richter said:
All I wanted to do was ask questions about an antenna that "appears" to work EVERY DAY! even when the propagation is poor.

As already said, any respectable antenna will work if the propagation exists

Jackson Richter said:
By the way Dave, we have a Dr.Gupta here in Cedar Rapids that is also a storm chaser and loves it.
I hope everyone has a good day.

Not familiar with the name ...
And an awesome day to you :smile:

Dave
and since we are exchanging callsigns

de VK2TDN, ex ZL4TBN, licenced since 1980 and crazy about the microwave bands in particular
where antennas and plumbing go hand in hand
 
  • #40
Well Dave, A lot of testing is basically being done every day. You are right, there has been no side by side comparison from the G5RV and the OCF. There hasn't been any RF field strength testing either. I don't have any empirical data to show comparisons of the many antennas, except for the many stations that I talk to every night. I guess I have failed to say it properly. Being from the old school, I like to do things by the book, believe it or not. If an antenna works well, the empirical data should show it, along with the design data proving that it works. Also the field testing with the countless hours should prove something too. I am getting older and sometimes the grey matter doesn't kick in right away. lol. It takes a lot of thought process to hammer it in.
I think a resonant dipole performs very well. There is no argument here. Your trapped dipole I'm sure works well also. I would like to mention again that this antenna is not only broadband but also multiband operation too. It works on 80m, 40m, 20m and 10m and 6m. I am not sure why you said it isn't. I have used this antenna on these bands when the propagation was there. I have many antenna plots of this antenna with a AIM4170 impedance analyzer. If you would like to see them, I would be glad to send them to you. I also would like to mention that I agree about the VSWR. Just because your VSWR is flat that doesn't mean your antenna is efficient. It just means your matched to the load. I also know from old school that a center fed antenna with open wire feed line has been used for multiband operation for many years. I also know many operators that have used this type of antenna all of their lives with success but a tuner is required to match resistive and reactive properties of the feed line and antenna. I personally don't like the open wife feed, its cumbersome and pretty hard to hide, but it is very low loss. The prior studies of the OCF antenna left so many holes. I am trying to gap these holes and make it more palatable, for guys like yourself and Baluncore, lol. I will refrain from the over zealous remarks. This OCF has a lot to offer, its a wide bandwidth and a multiband antenna, which "appears" to work well because of the consistent daily reports from other amateurs. I will say now that it may not out perform a standard dipole, but it will be very close. Your right Dave, it may not out perform even your antenna but it will go where yours can't and do it surprising well. Sometimes I feel like the little Dutch boy with his finger in the dyke plugging all the holes. Maybe someday I'll have all empirical data needed to show the how and why of this antenna. Thanks again to you and Baluncore for keeping my head straight, we need that every now and then.

JR Richter
 
  • #41
Because it is horizontally polarised at the design wavelength and is close to the ground, any induced ground currents will cancel the transmitted signal. A vertical over a ground plane does not suffer that problem.

Jackson Richter said:
This OCF has a lot to offer, its a wide bandwidth and a multiband antenna, which "appears" to work well because of the consistent daily reports from other amateurs. I will say now that it may not out perform a standard dipole, but it will be very close.
Not very close. The pattern will be dipole shaped but several dB down on a true dipole.

The resonant dipole is designed so that impedance of the wire remains constant along the dipole. An inverted V has height variation. If the diameter of the wire, (or the cage of wires), is not adjusted to be proportional to height from ground, (and nearby conductive features), then there is constant impedance mismatch and smear of the phase along the wire. That kills the Q of the resonance and goes a long way to explaining why it has low SWR, especially on the shorter wavelengths. For that reason it can never match or even get close to a true dipole.
 
  • #42
Jackson Richter said:
It works on 80m, 40m, 20m and 10m and 6m. I am not sure why you said it isn't.

Baluncore and I are telling you it isn't multiband because it isn't resonant on other bands without tuning
That is the difference between broad band and multiband. They are not the same thing ... very different meanings
Where as my trapped dipole is truly multiband, it will work on multiple bands WITHOUT tuning for each of those bands
because it is already resonant on them and any other bands that are harmonically related

I built my trapped dipole to cover 40, 20, 15 and 10. I couldn't care about 80m it's way too noisy to use from the burbs of a large city
and I also have huge 220kV transmission lines about 1 km from home that add to the S9+++ noise on 80m ... even 40m is pretty noisy
rarely gets below an S5

for 6m I have always used yagis, in the days when I was really active on 6, I had 6ele on a 6m boom, see the ARRL antenna handbook from ~ the '70's
an amazing performer. Cant use that from my current location within the depths of Sydney city ... am restricted to a 3 ele yagi and its 6dBi gain

I suspect your OCF won't be producing any signif. gain on 6m ( someone can prove me wrong :wink: )

Jackson Richter said:
Your right Dave, it may not out perform even your antenna but it will go where yours can't and do it surprising well.

not sure what you mean by that ?

My ultimate HF antenna would be the SteppIR ... I can only dream :rolleyes:

http://www.steppir.com/4-element-yagi
cheers
Dave
 
  • #43
davenn said:
Baluncore and I are telling you it isn't multiband because it isn't resonant on other bands without tuning
I what I am telling you "nicely" no tuner is required on the other bands.
 
  • #44
davenn said:
and I also have huge 220kV transmission lines about 1 km from home
Being that close to the power line is certainly a determent on 80m. What I can suggest is a listening antenna like a beverage type, that is directive for only one direction. We work a station in Florida every night on 80m with similar problems. He receives on the beverage and transmits on a different antenna.
 
  • #45
davenn said:
My ultimate HF antenna would be the SteppIR ... I can only dream :rolleyes:
Dave I do agree, very nice antenna. I also have one for you and think you will get a kick out of it. If you can go on You Tube and type in KB9RBL, (who is one of the antenna installers), you will witness the installation of a 80m 3 element array (3000 lbs) at 140 ft. The gentleman who owns this is a retired pastor.
 
  • #46
I am wasting my time when the OP sees brand as more important than functionality.
I must abandon this thread as it is not about physics.
 
  • #47
Jackson Richter said:
I what I am telling you "nicely" no tuner is required on the other bands.

HUH ??

you have already admitted in your post #27 and agreed with Baluncore's post #23 that because of the constantly changing feedpoint impedance with freq
that a tuner will be required

So you now don't think that it will be ? how are you going to match your TX with the widely varying input impedance without a transmatch ?
Dave
 
  • #48
davenn said:
So you now don't think that it will be ? how are you going to match your TX with the widely varying input impedance without a transmatch ?
I don't mean to lead you astray. There is variance in the impedance. This variation is not extreme. The feed point impedance is between 100 and 200 ohms when the feed point is located about 1/3 the distance from the end of a half wave dipole. For instance, if your 1/2 wave antenna is designed for 3.6 MHz and fed the antenna in the center 1/4 wave length position the input impedance will be approx. 73 ohms when mounted a wave length or higher. This have wave length is about 40m. If we feed this antenna at 13.6m from the end, a finite impedance can be calculated. The impedance is around 100 ohms at 3.6 MHz. The impedance formula will support this as well. As Baluncore mentioned, the near field also effects the input impedance and he is right, it does. If this antenna is raised higher, this near field will effect it less, but will still affect it as same as the dipole. Now by keeping the feed point at this location, this antenna can be operated at 2nd, 4th, 8th harmonic with pretty much the same impedance. The equations will also support this. A 4:1 balun is used here at this feed point making the impedance more manageable. I do have all the data to support this. When this antenna is put into a inverted v configuration the impedances of course change. The findings so far that this antenna has a optimized height of around 13m. No, the VSWR is not perfect but it seems to broad band, even across other bands. That's what I know Dave. The highest VSWR is about 2.0 : 1. If this is too hard for you and Baluncore to except well I can't do anything about that. My hope here was get help not be chastised. Again I may find out its all muddied and skewed because of the type of antenna I'm using. That's the purpose of this thread, was to learn and not to be cut off at the knees because I didn't agree with you. Again sorry Baluncore for wasting your time. At least Dave your personality didn't resemble that of a rock. Thank you for that.

JR Richter
 
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  • #49
Jackson Richter said:
If this is too hard for you and Baluncore to except well I can't do anything about that. My hope here was get help not be chastised.

Please don't think you are being chastised ... far from it :smile:

As I said earlier a couple of times, just don't let your enthusiasm override the science
comments like "this antenna sounds better than that one" is not scientific evidence
antennas don't affect the audio quality, but I'm sure you really do know that :wink:

when you have done real testing, including side by side performance tests,
I encourage you to show us the results :smile:
regards
Dave
 
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  • #50
Jackson Richter said:
The highest VSWR is about 2.0 : 1. If this is too hard for you and Baluncore to except well I can't do anything about that.
I accept that is the case. Indeed that is exactly what is expected of a high loss system.

You should understand that SWR works both ways.
When the antenna is perfectly matched you have an SWR of 1.0
When because of feedline losses, no energy gets back from a mismatched antenna, you will also have a low SWR.

By de-tuning a resonant antenna it should be possible to reflect almost all the energy. If you cannot get a high SWR of 10:1 from a resonant antenna, mismatched to it's feedline, then you have problems with your feedline.

It is always interesting to short circuit the antenna terminals at the balun, then look for the maximum SWR.
 
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