Instantaenous velocity/center of mass? help

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SUMMARY

The discussion focuses on calculating the instantaneous velocity of a wedge system involving a 10 kg wedge and a 5.0 kg block sliding down its inclined surface. The block has vertical and horizontal velocity components of 3.0 m/s and 6.0 m/s, respectively. The key concept is the conservation of momentum and the center of mass motion, which dictates that the horizontal motion of the block will cause the wedge to move in the opposite direction. The equation of motion for the center of mass is essential for solving this problem.

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Homework Statement



A large wedge with a mass of 10 kg rests on a horizontal frictionless surface, as shown. A block with a mass of 5.0 kg starts from rest and slides down the inclined surface of the wedge, which is rough. At one instant the vertical component of the block's velocity is of 3.0 m/s and the horizontal component is 6.0 m/s. At that instant the velocity of the wedge is:

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The Attempt at a Solution


I'm not really sure where to get started... I think it has something to do with the center of mass but not sure what. Also, I'm confused as to how the block can cause the wedge to move. Can someone help me get started?
 
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