(adsbygoogle = window.adsbygoogle || []).push({}); vAn objects moves horizontally according to the following equation s(t)=t^{3}-2t^{2}-5t+6. Determine the instantaneous velocity of the object at t0=1 second using the definition of a derivative at a point.

v'(t)= lim (s(t_{0}+h)-s(t_{0}))/h

h-->0

And

What is the average velocity of the object from t=0 to t=2?

Average velocity= (s(t_{2})-s(t_{1}))/(t_{2}-t_{1})

For the first one, i got:

((1+h)^{3}-2(1+h)^{2}-5(1+h)+6-1^{3}-2(1)^{2}-5(1)+6)/h

I expanded and factored all of that ang got (h(-1+h+h^{2})/h then i plugged in 0 for h and got -1 as the instantaneous velocity... is that correct?

I got the first one... i just added the values wrong... i got -6. But i still dont know how to do the second one.

and for the second one, i have (3(2)^{2}-4(2)-5)/2-0 but that makes it 0/2 and i know that this cant be.

Can you please help me?thank you!

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# Homework Help: Instantaneous and average velocity help

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