vAn objects moves horizontally according to the following equation s(t)=t3-2t2-5t+6. Determine the instantaneous velocity of the object at t0=1 second using the definition of a derivative at a point. v'(t)= lim (s(t0+h)-s(t0))/h h-->0 And What is the average velocity of the object from t=0 to t=2? Average velocity= (s(t2)-s(t1))/(t2-t1) For the first one, i got: ((1+h)3-2(1+h)2-5(1+h)+6-13-2(1)2-5(1)+6)/h I expanded and factored all of that ang got (h(-1+h+h2)/h then i plugged in 0 for h and got -1 as the instantaneous velocity... is that correct? I got the first one... i just added the values wrong... i got -6. But i still dont know how to do the second one. and for the second one, i have (3(2)2-4(2)-5)/2-0 but that makes it 0/2 and i know that this cant be. Can you please help me?thank you!