- #1

Jbreezy

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## Homework Statement

I have to use the comparison test although I'm bad at coming up with what to compare it to

## Homework Equations

What if I compare it to 1/sqrt(x)

## The Attempt at a Solution

I take the integral of 1/sqrt(x) from [0,PI] I get -2sqrt(x) and then I use limits and evaluate

I get 2sqrt(PI)

Can I do this? So since this integral is larger then the one in question my integral converges?