Integral of an exponential divided by a root function

AI Thread Summary
The discussion focuses on proving that the diagonals of a parallelogram bisect each other. The user defines the vertices of the parallelogram using vectors, with one vertex at the origin and others at points a and b. They express the diagonals in vector form as r1 = a + b and r2 = b - a. Questions arise about whether it's necessary to prove that the diagonals intersect at the center and the definition of a vertex. The user seeks clarification on how to determine the midpoint of the diagonal represented by the vector b - a.
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Homework Statement



Prove that the diagonals of a parallelogram bisect each other.

Homework Equations



I chose one vertex as the origin, one as a and one as b. The final vertex was a+b.

The Attempt at a Solution



The diagonals were \vec{r_1}=\vec{a}+\vec{b} and \vec{r_2}=\vec{b}-\vec{a}. Where do I go from here? Can I assume that they go through the center of the parallelogram or do I have to prove that too?
 
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What is the definition of a vertex?
 
Err... a point where two vectors intersect?
 
Your vectors "begin" at one vertex, right? What vector, starting at that vertex, has its "end" at the midpoint of \vec{a}+ \vec{b}? \vec{b}-\vec{a}?
(Note that, since \vec{b}-\vec{a} "starts" at \vec{a} instead of the origin, the midpoint of \vec{b}-\vec{a} is at \vec{a} plus half of \vec{b}-\vec{a}.)
 
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