: Integral of (n+1)th derivative

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URGENT: Integral of (n+1)th derivative

Homework Statement



let f(n+1) be integrable on [a;b]; show that

f(b)=\sum \frac{f<sup>(r)</sup>(a)}{r!}(b-a)r +\frac{1}{n!} \int^{a}_{b}f(n+1)(t)(b-t)ndthint:integrate by parts and use inductionPLEASE any idea about how to solve it would be really appreciated... I've been trying for more than an hour but no idea
 
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Well use the hint. Induct on n. For n = 1, show the equation holds by computing the integral that you get on the RHS after setting n = 1. This is fairly straightforward.
 


Start by actually doing the integration by parts. Treat the integral as u*dv where u=f^(n+1)(t) and dv=(b-t)^n*dt. Once you've got that straight then start worrying about the induction.
 


10x a lot
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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