Integrate √1+x^2 - Solutions & Explanations

Nathan Wygal
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1. The problem is as follows: ∫(√1+x^2)dx/(x) 2. Using trig sub --> x = atanΘ with a = √1 = 1. So x = tanΘ and dx = sec^2ΘdΘ. 3. Picture included of attempted solution. I tried u substitution with both u = secΘ and u=tanΘ but didn't have the right du. I then tried breaking the sec^3Θ/tanΘ (second to last step shown in work) into sines and cosines but, once again, no luck. Any help would be greatly appreciated.

Note: I hope the format of my question is adequate this time. Sorry for the last post.
 

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As I previously suggested, try multiplying numerator and denominator by ## \sin(\theta) ## and letting ## u=\cos(\theta) ## after a little algebra. (e.g. ## \sin^2(\theta)=1-\cos^2(\theta)) ## Then try using partial fractions to get the integral expression involving "u" in workable form.
 
You could also try a hyperbolic trig substititution: ##x = \sinh u##.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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