How Do I Integrate sqrt(4x) + sqrt(4x) on the Interval 0 to 1?

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To integrate sqrt(4x) + sqrt(4x) over the interval from 0 to 1, first simplify the expression to 2*sqrt(4x) or 4*sqrt(x). The integral can be calculated as 4 times the integral of sqrt(x) from 0 to 1, which results in 4*(2/3) = 8/3. The initial calculation of (8^3/2)/3 is incorrect due to a misunderstanding of the integration process. The correct answer for the definite integral is 8/3.
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Ok, I've been doing work for about 4 hours straight and I think my brain is fried. I know this is easy, it is just not working in my head.

Anyway, the problem is this:

Integrate the sqrt(4x) + sqrt(4x) on the interval 0 to 1

I get, (8^3/2)/3 + (8^3/2)/3 but apparently this is not right. I'm probably forgetting something I'll hit myself in the head for :cry: . Any help though?

Thx,
MathGnome
 
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This is answered in Calculus & Analysis.
 

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