Integrate the on axis field of finite solenoid from a thin shell one, HELP

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SUMMARY

The discussion focuses on integrating the on-axis magnetic field of a finite solenoid derived from the thin shell solenoid equation. The user, Samuel, references specific equations from the provided links and seeks clarification on obtaining the (r2-r1) term in the finite solenoid equation. The solution involves integrating the magnetic field contribution from infinitesimal solenoids of radius r, thickness dr, and length l, using the expression dB = (μ₀N di / 2l) * [(x₂ / √(x₂² + r²)) - (x₁ / √(x₁² + r²))]. The key to solving the problem lies in expressing di in terms of dr through current density.

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demon_samuel
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Dear all,

i met a problem that i couldn't get the on axis field of a finite solenoid that integrating from a thin shell solenoid equation.

The thin shell equation link:
http://www.netdenizen.com/emagnet/solenoids/thinsolenoid.htm

And the on axis finite solenoid equation link:
http://www.netdenizen.com/emagnet/solenoids/solenoidonaxis.htm

If i was right, the integral of (a/sqrt (a*a+r*r)) dr should be a*ln(r+sqrt(r*r+a*a)), if so i couldn't figure out how to get the (r2-r1) term in the second link equation.

Thank you for your attention

Samuel
 
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To get the second expression from the first, you need to integrate over dr from r1 to r2. You do this by adding "solenoids" of radius r, thickness dr, and length l carrying current di. According to the first expression, the contribution from one such solenoid is

[tex]dB = \frac{\mu_{0}N di}{2 l}[\frac{x_{2}}{\sqrt{x^{2}_{2}+r^{2}}}-\frac{x_{1}}{\sqrt{x^{2}_{1}+r^{2}}}][/tex]

Before you integrate, you need to express di in terms of dr. Hint: Think in terms of current density.
 
Thank you very much, i got the answer.
 

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