Integrating (2/a)[200sin(3πx)sin(nπx/a)] from 0 to a

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Homework Statement



I need to integrate


(2/a) [200sin(3*Pi*x)sin(n*pi*x/a)] from 0 to a. In this equation , 'a' is a constant. I don't have to show my work, just the final answer.





Homework Equations





The Attempt at a Solution


I used a website, and got a result which I have attached. This online calculator does not plug in the bounds. However, this doesn't seem correct to me. I tried to integrate it by parts (to check), but couldn't get it to work. Any help? Thanks.
 

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If you only want to find an answer you can use www.wolframalpha.com and tell it:
"integrate f(x) dx from 0 to a"
where f(x) is your function.

However, it is always good to know how to do stuff by hand. I think two integrations by parts should work.
 
Ok so what I inputted was this...

integrate (2/a)[200sin(3*Pi*x)sin(n*pi*x/a)dx from 0 to a

I couldn't get it to give me a definite result. It gave me an indefinite result, but I would like to learn how to use this site properly too.
 
Ohhh ok. Thanks.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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