- #1
Blade
- 12
- 0
Need a kickstart with this one:
f(t)=t^(3/2)log(of 2)Sqrt(t+1)
Integral of (3-x)7^[(3-x)^2] dx
7^[(3-x)2] = e^[(3-x)2ln 7]
u=(3-x)^2
du/dx = -2(3-x)
(3-x)dx = -1/2 du
not even sure what so far is right..
f(t)=t^(3/2)log(of 2)Sqrt(t+1)
Integral of (3-x)7^[(3-x)^2] dx
7^[(3-x)2] = e^[(3-x)2ln 7]
u=(3-x)^2
du/dx = -2(3-x)
(3-x)dx = -1/2 du
not even sure what so far is right..