Integrating a Matrix: Simplifying the Process

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Hi everyone. I was curious how I could integrate a matrix. Is it just as simple as separately integrating each of the entities of the matrix, or is it more complex than that?
 
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wow u can do that? :O
 
Well to differentiate a matrix, you would differentiate of all the entries...so i guess integrating would just be integrating each element

http://comp.uark.edu/~jjrencis/femur/Learning-Modules/Linear-Algebra/mtxcalc/integration/integration.html

for more info
 
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rock.freak667 said:
Well to differentiate a matrix, you would differentiate of all the entries...so i guess integrating would just be integrating each element

http://comp.uark.edu/~jjrencis/femur/Learning-Modules/Linear-Algebra/mtxcalc/integration/integration.html

for more info
very interesting, what class do i do that in? linear algebra?
 
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I think so, but I am covering it in quantum mechanics. Thanks for the help!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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