Integrating Complexity: Solving \int \frac{1}{x^n(1+x^n)^{1/n}} \;\mathrm{d}x}

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Homework Statement



An Integral : <br /> <br /> \int \frac{1}{x^n(1+x^n)^{1/n}} \;\mathrm{d}x}<br /> <br />

Homework Equations



The Standard integrals.

The Attempt at a Solution



I'm aware that integrals like this become very easy after a clever substitution...but maybe I'm not that clever :frown: so I can't even start it. If anyone shows me the first step I'll try to take it from there.
 
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Fixed your latex:

<br /> \int \frac{1}{x^n(1+x^n)^{1/n}} \mathrm{d}x<br />
 
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ideasrule said:
Fixed your latex:

<br /> \int \frac{1}{x^n(1+x^n)^{1/n} \mathrm{d}x}<br />

have you tried bring the (1+x^n)^(1/n) to the top? It would become (1+x^n)^n.

You've left the dx at the bottom :wink:
but how will it become (1+x^n)^{n}? Bringing it to the top will change the sign of the exponent, right?
 
Rats_N_Cats said:
You've left the dx at the bottom :wink:
but how will it become (1+x^n)^{n}? Bringing it to the top will change the sign of the exponent, right?

Yes, I got confused. Sorry about that.
 
I tried letting xn = t, but that ended up with <br /> \frac{1}{n} \int \frac{1}{\sqrt[n]{t^2+t}}\:\mathrm{d}t<br />, And I don't see how to do it.
Then I tried letting xn+1 = tn, and got something similarly unsolvable. Can anyone tell me what's the right substitution in this case?
 
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Here's something:

\int x^{-n}(1+x^n)^{-1/n} \mathrm{d}x

And integrate by parts from there. Dunno if it works, though. I tried it on W-A and they used a weird substitution within a substitution.
 
I did that, letting (1+xn)-1/n as first function, and I ended up with :
<br /> \frac{x^{1-n}}{1-n}\,(1+x^n)^{-1/n} + \frac{x}{1-n} + \frac{x^{n+1}}{1-n^2} + C<br />
Is that correct?
 
Maybe. I'm too tired to check now. It looks right.
 
Will anyone please confirm if my answer is correct or not? This problem's been bugging me for quite some time.
 
  • #11
try trigonometric substitution
 
  • #12
Hello!
What trig substitution can you make? PM me if the OP wants to work it out themselves.
Thanks!
 

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