Integrating e^x/(e^{2x} + 1): Long Division?

AI Thread Summary
The discussion focuses on the integral ∫(e^x/(e^{2x} + 1) dx and the challenges of rewriting it to fit the arctan formula. Participants suggest that long division may not be necessary, emphasizing the effectiveness of u-substitution, specifically using u = e^x. The conversation highlights the importance of u-substitutions in simplifying integrals and solving problems efficiently. Overall, the consensus is to embrace u-substitution as a valuable tool in integration. Understanding these techniques can significantly ease the process of solving complex integrals.
RadiationX
Messages
255
Reaction score
0
i'm having trouble rewriting this integral:\int\frac{e^x}{e^{2x} + 1} so that it will be in the arctan formula: should i use long divison here? if it were not for the e^x in the numerator i'd be fine.
 
Last edited:
Physics news on Phys.org
u = e^{x}, du = e^{x}dx

e^{2x} = (e^{x})^2
 
you never get away from u -substitutions do ! thanks
 
Why woudl you watn to get away from them? They save your ass a lot :)
Learn to love em.
 
yeah your right
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top