Integrating in Spherical Co-Ordinates.

AI Thread Summary
The discussion focuses on integrating a specific triple integral in spherical coordinates. The original integral is transformed correctly, but the user initially struggles with formatting the limits in LaTeX. After resolving the formatting issue, the conversation shifts to integration techniques, suggesting that integration by parts or a substitution could be effective. The correct integrand in spherical coordinates is identified as \(\frac{\rho^{2}\sin\phi}{1+\rho^{2}}\). The user expresses gratitude for the assistance received in clarifying the integration process.
Chaz706
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I have the following Integral

\int ^1 _0 \int _0 ^\sqrt{1-x^2} \int _0 ^\sqrt{1-x^2-y^2} \frac{1}{1+(x^2)+(y^2)+(z^2)} dzdydx

(With the limits working properly!)

Converted to spherical Cor-ordinates, I have

\int ^\frac{\pi}{2} _0 \int _0 ^\frac{\pi}{2} \int _0 ^1 \frac{1}{1+\rho} \rho^2 sin(\phi) d\rho dr d\phi

I've converted the function, but how would I start integrating?
 
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Alright.Transform it in spherical coordinates.But u need the limits...

Daniel.
 
I have the limits... it's just that I can't get them right on Latex (stupid coding! I'm getting it right, it's just not displaying it that way!)

Hang on...

EDIT: Problem above now has working limits, and my original question as intended.
 
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A substitution MIGHT work, but i would probably go for integration by parts. Remember sin(phi) is constant for the first integral.
 
\frac{r^{2}}{1+r}=r-1+\frac{1}{1+r}

is all u need.

Daniel.
 
Your integrand in spherical coordinates should be: \frac{\rho^{2}\sin\phi}{1+\rho^{2}}
 
I've got this thanks. Thanks to a form of integration in the back of my book.
 
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