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edit: Nevermind, I realized a way to find the answer after posting it. Though I still don't know about the thing involving the notes, can someone confirm if what I have written down as my teacher doing is true?

note: I'll use this

With a ln x type function being divided by a power of x, I did the obvious and made u = ln x and du = 1/x dx, but that still leaves x^-2. I don't know how to get from here.

I just saw this problem in my notes and am not sure if I made an error when writing, but what my teacher appears to have done is made the same substitution I did, and then wrote

I don't know how one makes that, and when I plug back the substitution I don't arrive at the original equation. I get e^(-2 ln x)*dx/x = (x^2)/x * dx (I split e^-2 ln x into (e^-ln x)(e^-ln x) = -x^2. So I think I just wrote something down wrong, but in any case, I still do not know how to go beyond that simple substitution I made earlier.

edit: I just needed to integrate by parts with ln x = u and dv = 1/x^3

## Homework Statement

note: I'll use this

*S*as an integral symbol.*S*(ln x)/x^3## Homework Equations

## The Attempt at a Solution

With a ln x type function being divided by a power of x, I did the obvious and made u = ln x and du = 1/x dx, but that still leaves x^-2. I don't know how to get from here.

I just saw this problem in my notes and am not sure if I made an error when writing, but what my teacher appears to have done is made the same substitution I did, and then wrote

*S*(ln x)/x^3 =*S*e^(-2u) du.I don't know how one makes that, and when I plug back the substitution I don't arrive at the original equation. I get e^(-2 ln x)*dx/x = (x^2)/x * dx (I split e^-2 ln x into (e^-ln x)(e^-ln x) = -x^2. So I think I just wrote something down wrong, but in any case, I still do not know how to go beyond that simple substitution I made earlier.

edit: I just needed to integrate by parts with ln x = u and dv = 1/x^3

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