- #1
physguy09
- 18
- 0
So I need to inegrate over a solid angle, in which every possible orientation is considered (we are doing scattering events in which we assume every possible angle is possible), thus I need to solve
\int d\Omega_1 d\Omega_2 d\Omega_3 Eqn (1).
Now I know
\int^{2 \pi}_{0} \int^{\pi}_{0}d\Omega = \int^{2 \pi}_{0} \int^{\pi}_{0} sin(\theta)d\theta d\phi = 2\pi \int^{\pi}_{0} sin(\theta) d\theta = 2\pi (-cos(\theta))^{\pi}_{0} = 4 \pi
so shouldn't that mean that Eqn (1) should integrate to 64 \pi^3?
\int d\Omega_1 d\Omega_2 d\Omega_3 Eqn (1).
Now I know
\int^{2 \pi}_{0} \int^{\pi}_{0}d\Omega = \int^{2 \pi}_{0} \int^{\pi}_{0} sin(\theta)d\theta d\phi = 2\pi \int^{\pi}_{0} sin(\theta) d\theta = 2\pi (-cos(\theta))^{\pi}_{0} = 4 \pi
so shouldn't that mean that Eqn (1) should integrate to 64 \pi^3?
Last edited:
)
