Integrating the Yukawa Potential: Understanding the 3rd Step

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Discussion Overview

The discussion revolves around the integration of the Yukawa potential, specifically focusing on the steps involved in resolving the integral as presented in a reference. Participants are seeking clarification on the integration process, particularly the third step.

Discussion Character

  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant outlines the steps involved in the integration, starting with converting to spherical coordinates and integrating out the azimuthal angle.
  • Another participant describes the second step as resulting in a difference of exponentials, suggesting a preference for not expressing it in terms of sine.
  • There is mention of two integrals, one with a positive exponential and the other with a negative exponential, and a change of variable from k to -k in the third step.
  • A participant expresses confusion about the third step, questioning the implications of changing the integration variable and the corresponding differential.
  • Another participant reiterates the steps provided earlier, indicating they understand the process but seeks further clarification on the third step.

Areas of Agreement / Disagreement

Participants generally agree on the steps involved in the integration process, but there is a lack of consensus regarding the specifics of the third step, particularly the change of variable and its implications.

Contextual Notes

There are unresolved questions regarding the treatment of differentials when changing integration variables, as well as the limits of integration, which have not been explicitly addressed in the discussion.

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1st step: go to "spherical coordinates" and integrating out the \phi... u = \cos \theta
2nd step: Integrating wrt to u, will give a difference of e^{i~something} - e^{-i~something} \propto \sin (something). In fact I wouldn't ever write it in terms of sin...
3rd step: uses that he has two integrals one with the exponential with + and the other with the exponential with - ... then changes the integration variable of the one from k to -k, and gets this result.
4th step: factorizes the denominator.
5th step and then final: solves the (complex) integral

If you want to see a step in more details, you can ask for a specific one.
 
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I actually get it with your points! Thank you very much!
 
ChrisVer said:
1st step: go to "spherical coordinates" and integrating out the \phi... u = \cos \theta
2nd step: Integrating wrt to u, will give a difference of e^{i~something} - e^{-i~something} \propto \sin (something). In fact I wouldn't ever write it in terms of sin...
3rd step: uses that he has two integrals one with the exponential with + and the other with the exponential with - ... then changes the integration variable of the one from k to -k, and gets this result.
4th step: factorizes the denominator.
5th step and then final: solves the (complex) integral

If you want to see a step in more details, you can ask for a specific one.
hello sir,
i can't get the 3rd step. is change the integration variable, change the value from k to -k in that term, including the dk -> d(-k)?
 
Muh. Fauzi M. said:
i can't get the 3rd step. is change the integration variable, change the value from k to -k in that term, including the dk -> d(-k)?

like everytime you change your integration variable from x to y(x) what has to change is of course the differential, the integrand and the limits of the integral.
 

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