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rock_star
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Homework Statement
Integrate x^5sin(x^3). Using Integration by parts.
The Attempt at a Solution
I don't know which one to take du and u
can anyone please help me out?
Thanks a lot before hand!
rock_star said:Homework Statement
Integrate x^5sin(x^3). Using Integration by parts.
The Attempt at a Solution
I don't know which one to take du and u
can anyone please help me out?
Thanks a lot before hand!
roam said:Remember the rule known as "LIATE" (aka: Logarithmic-Inverse Trigonometric-Algebraic-Trigonometric-Exponential) the one which comes first is your u and the one which appears later is your dv.
In your question u=x5 because it is algebraic and dv=sin(x3) since it's trigonometric.
roam said:I agree with you, I didn't notice that . I think the OP wanted to find a general rule for choosing u and dv when the integrand is a product of two functions from different categories in the list "LIATE" - in this case you will often be successful if you take the u to be the function whose category occurs earlier in the list and take dv to the rest of the integrand. The acronym LIATE helps one to remember the order but doesn't work in this case, I noticed that can't integrate sin(x^3).
Anyway using rasmhop's substitution did you get: [tex]\frac{1}{3} sin(x^3) - \frac{1}{3} x^3 cos(x^3)[/tex] or is your answer different?
n!kofeyn said:Yea, but that doesn't help, because how will you integrate dv=sin(x3)? rasmhop's excellent advice is what rock_star should follow.
I've never even heard of the "rule" LIATE, and to me, it is more confusing than just understanding how integration by parts works.
The formula for integrating x^5sin(x^3) is ∫x^5sin(x^3)dx = -1/3cos(x^3)+C
No, x^5sin(x^3) cannot be integrated using the power rule because the power rule only applies to functions in the form of x^n, where n is a constant.
The best method for integrating x^5sin(x^3) is using integration by parts, where one part of the integrand is differentiated and the other part is integrated.
No, there is not a specific shortcut for integrating x^5sin(x^3). However, knowing the rules and techniques for integration can make the process faster and easier.
Yes, the integral of x^5sin(x^3) can be evaluated using substitution by letting u = x^3. This will result in the integral becoming ∫(1/3)u^2sin(u)du, which can then be integrated using integration by parts.