Integrating (x-9)4^x Using Integration by Parts | Homework Help

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Homework Statement


I have to evaluate the integral of (x-9)4^xdx


Homework Equations


Integration by parts



The Attempt at a Solution


I setted the (x-9) as D and the 4^x as I. The problem is that I am not sure what the antiderivative of 4^x would be. I am guessing its mostly like 4^x+1 all over x+1. If this is true, then there is another problem. I am not sure of how i could integrate 4^x+1(x+1)^-1. Help is desperate at this moment, since i only have 6 hours to submit my homework. Please give me support. Thanks.
 
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4^x is a lot like e^x. In fact, it is e^(ln(4)*x). That's easy to integrate.
 
Dick said:
4^x is a lot like e^x. In fact, it is e^(ln(4)*x). That's easy to integrate.

thank you very much for the assistance.
 
alright Ill try that, thanks for the advice. And by the way do you perhaps know the antiderivative of e^(ln(4)*x)? Because on this one certain problem i had to find the antiderivative of 4^x which i found to be e^(ln(4)*x) but i can't seem to know how to find the antiderivative of e^(ln(4)*x). Is it perhaps e^(ln(4)*x) all over ln(4)x?

thank you for taking your time to help me out. Really appreciate it.

Keep only one thread for one problem.

What's the anti-derivative of e^(x)?
What's the anti-derivative of e^(a.x)?
So, a = ln(4)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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