- #1
Daveami
- 8
- 0
Hi there,
I am having difficulty with one aspect of intergration by substitution where the substituion of a square root is U^2, wondering if anyone can help.
Problem:
Integral of: 2x√(3x-4) dx by substituting U^2 = 3x-4
Would du^2/dx = 3 therefore 1/3 du^2 = dx (I think this is where I am going wrong)
Im coming out with an answer of: 2/45(9x+8)(3x-4)^3/2 + k
However the answer in the book is: 4/135(9x+8)(3x-4)^3/2 + k
Any help would be greatly appreciated.
Regards
Dave
I am having difficulty with one aspect of intergration by substitution where the substituion of a square root is U^2, wondering if anyone can help.
Problem:
Integral of: 2x√(3x-4) dx by substituting U^2 = 3x-4
Would du^2/dx = 3 therefore 1/3 du^2 = dx (I think this is where I am going wrong)
Im coming out with an answer of: 2/45(9x+8)(3x-4)^3/2 + k
However the answer in the book is: 4/135(9x+8)(3x-4)^3/2 + k
Any help would be greatly appreciated.
Regards
Dave