Integration involving spherical harmonics

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SUMMARY

The integral ∫∫dΩ V(Ω)Yml(Ω) for the piecewise function V(Ω) = +V0 for 0<θ<π/2 and -V0 for π/2<θ<π requires splitting the integral into two parts over the upper and lower halves of the sphere. The orthonormality properties of spherical harmonics are not directly applicable due to the nature of the integration. The solution involves integrating over φ first, leading to an integral that incorporates Legendre polynomials, ultimately resulting in zero due to the properties of the spherical harmonics.

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lordkelvin
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Homework Statement



Evaluate the integral ∫∫dΩ V(Ω)Yml(Ω) for V(Ω) = +V0 for 0<θ<π/2 ; -V0 for π/2<θ<π


Homework Equations


I was hoping to apply the orthonormality properties of the spherical harmonics but this is a little more difficult since the integral breaks into two integrals over half spheres instead of one integral over a full sphere.

I guess it may be useful to rewrite the V(Ω) as ±√(4π)Y00(Ω)V0 in order to invoke the orthogonality properties of the spherical harmonics when integrated on a sphere.


The Attempt at a Solution



Basically I've split the integral into two integrals over the upper and lower halves of the sphere. Now what? Surely I'm not to use the definition of the spherical harmonics; there must be a cleaner way to do this by invoking the properties of Ylm(omega). There is nothing I can say about ∫∫half of spheredΩYlm(Y00)* as far as I know. Is there some way to combine the two integrals again so that I can use the orthonormality property?
 
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Orthonormality won't really help here because you're not integrating the product of two spherical harmonics. The integral should be pretty straightforward though. Start by integrating φ out first. Then you'll be left with an integral involving a Legendre polynomial.
 
I get zero. I think this is so since Ylm(θ,\phi) = const* e^(i*\phi)*Plm(cos(\theta) and so the integral over phi yields zero.
 
It's e^{im\phi}, not e^{i\phi}. It makes a difference.
 
Last edited:

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