Integration of a function with it's derivative.

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SUMMARY

The integral ∫ t^3 * (t^2 + 1)^0.5 dt can be effectively solved using integration by substitution. The correct approach involves rewriting the integral as 0.5∫((t^2 + 1) - 1)(t^2 + 1)^(0.5)(2t dt). This method simplifies the integration process by applying the formula ∫f(g(x))g'(x)dx = ∫f(g)dg. The original attempt at using integration by parts was incorrect, highlighting the importance of selecting the appropriate integration technique.

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Homework Statement


Please help me by pointing me in the right direction for this integral :

∫ t^3 * (t^2 + 1)^0.5 dt


Homework Equations



i used the standard formula of integration by parts on this.

http://www.sosmath.com/calculus/integration/byparts/img9.gif

The Attempt at a Solution



here is what is did :
1/2∫ 2t * t^2 * (t^2 + 1)^0.5 dt
1/2{ [t^2 * (t^2 + 1)^1.5 * 2/3] - [∫ 2t * (t^2 + 1)^1.5 * 2/3 dt ]}

i highly doubt it is correct, i think i used the formula wrongly.

Can anyone point out my mistake or just provide me with any other sort of help, it would be appreciated.
 
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The title of your thread is "Integration of a function with it's derivative". The integral can be written as

\int{t^3(t^2+1)^{0.5} dt}=0.5\int{((t^2+1)-1)(t^2+1)^{0.5} (2tdt)} .

Apply "integration by substitution".

\int{f(g(x))g'(x)dx}=\int{f(g)dg}

ehild
 

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