Integration of Maxwell speed distribution function

Click For Summary
The discussion focuses on deriving the average molecular speed equation from the Maxwell speed distribution function. The user initially attempts to evaluate the integral of the function but encounters a zero result due to integrating an odd function over symmetric limits. Participants suggest changing the limits from negative to positive infinity, as speed cannot be negative, and emphasize the distinction between average velocity and average speed. Clarification is needed on whether the given function represents a probability density of velocity or speed. The conversation highlights the importance of proper integration limits and understanding the nature of the function involved.
theghost28
Messages
2
Reaction score
0

Homework Statement


Show the steps needed to obtain the equation for average molecular speed, cavg=√8RT/πM from the integral (from negative infinity to infinity) ∫v*f(v)dv where f(v) is the Maxwell distribution of speeds function f(v)=4π*(M/2πRT)1.5v2e-Mv2/2RT

M is the molar mass of the particle in kg/mol, R is the gas constant (8.314), v is particle velocity, e is the natural number and T is temperature in Kelvin.

Homework Equations


In the problem statement

The Attempt at a Solution


Capture7.PNG


I changed v from the problem to x for simplicity since I'm used to using v for integration by parts. I'm fairly sure this solution is correct, as I've googled what the integral of x3*ex2 is and others have obtained this as well. The problem is when I evaluate that expression from negative infinity to infinity, I get zero. I've gone over my math multiple times, is there something I'm missing?
 
Last edited:
Physics news on Phys.org
theghost28 said:

Homework Statement


Show the steps needed to obtain the equation for average molecular speed, cavg=√8RT/πM from the integral (from negative infinity to infinity) ∫v*f(v)dv where f(v) is the Maxwell distribution of speeds function f(v)=4π*(M/2πRT)1.5v2e-Mv2/2RT

M is the molar mass of the particle in kg/mol, R is the gas constant (8.314), v is particle velocity, e is the natural number and T is temperature in Kelvin.

Homework Equations


In the problem statement

The Attempt at a Solution


View attachment 98052

I changed v from the problem to x for simplicity since I'm used to using v for integration by parts. I'm fairly sure this solution is correct, as I've googled what the integral of x3*ex2 is and others have obtained this as well. The problem is when I evaluate that expression from negative infinity to infinity, I get zero. I've gone over my math multiple times, is there something I'm missing?
When you integrate the odd function vf(v) from -∞ to +∞, obviously you get 0.
Are you sure about the integration limits?

Maybe consider the following question: under what circumstances is speed negative?
 
I'm sure about the integration limits given in the assignment although I agree they don't really make sense. I guess I'll use 0 to infinity and make a note of it.
 
theghost28 said:
I'm sure about the integration limits given in the assignment although I agree they don't really make sense. I guess I'll use 0 to infinity and make a note of it.

Your calculation looks at average velocity, which is zero in this case. Average speed is different.

The first thing you need to figure out is whether the given ##f(v)## is a probability density of velocity or of speed. Can you see how to do that?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

Replies
5
Views
2K
Replies
3
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
605
  • · Replies 5 ·
Replies
5
Views
2K
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K