- #1
celeramo
- 9
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Homework Statement
Find the area enclosed by r=2cos(3[tex]\theta[/tex])
I'm fairly confident how to do this but for some reason I am getting 2[tex]\pi[/tex] rather than 1[tex]\pi[/tex], which the book claims is the answer. There is the possibility the book is wrong, but I want to make sure how to do this.
I have the area=(1/2)[tex]\int[/tex][tex]^{2\pi}_{0}[/tex] (2cos(3[tex]\theta[/tex]))^2 d[tex]\theta[/tex]
is this integral incorrect for the enclosed area?
Please and thank you very much :)